Chapter 5, Problem 56A

(a)

Interpretation Introduction

Interpretation: For the given values density in grams per cubic centimeter is needs to be calculate

Concept Introduction: The given volume of matter contained in a material is termed as density. That is, density is the mass per unit volume of an object:

  $\text{Density =}\frac{\text{mass}}{\text{volume}}$

Answer to Problem 56A

Density in grams per cubic centimeter is $1.53\text{g}/{\text{cm}}^{\text{3}}$ .

Explanation of Solution

Given values are as follows:

  $\begin{array}{c}\text{mass}=452.1\text{g}\\ \text{Volume}=292{\text{cm}}^3\end{array}$

Put above values in below equation.

  $\begin{array}{c}\text{Density =}\frac{\text{mass}}{\text{volume}}\\ =\frac{452.1\text{g}}{292{\text{cm}}^3}\\ =1.53\text{g}/{\text{cm}}^{\text{3}}\end{array}$

Hence, density is $1.53\text{g}/{\text{cm}}^{\text{3}}$ .

(b)

Interpretation Introduction

Interpretation: For the given values density in grams per cubic centimeter is needs to be calculate

Concept Introduction: The given volume of matter contained in a material is termed as density. That is, density is the mass per unit volume of an object:

  $\text{Density =}\frac{\text{mass}}{\text{volume}}$

Answer to Problem 56A

Density in grams per cubic centimeter is $0.51\text{g}/{\text{cm}}^{\text{3}}$ .

Explanation of Solution

Given values are as follows:

  $\begin{array}{c}\text{Volume}=125\text{mL}\\ \text{=125}{\text{cm}}^3\end{array}$

Since, $1\text{mL}=1{\text{cm}}^{\text{3}}$

Convert $0.14\text{lb}$ to g as follows:

  $\begin{array}{c}0.14\text{lb}=0.14\text{lb}\times \frac{453.59\text{g}}{1\text{lb}}\\ =63.50\text{g}\end{array}$

Put above values in below equation.

  $\begin{array}{c}\text{Density =}\frac{\text{mass}}{\text{volume}}\\ =\frac{\text{63}\text{.50}\text{g}}{125{\text{cm}}^3}\\ =0.51\text{g}/{\text{cm}}^{\text{3}}\end{array}$

Hence, density is $0.51\text{g}/{\text{cm}}^{\text{3}}$ .

(c)

Interpretation Introduction

Interpretation: For the given values density in grams per cubic centimeter is needs to be calculate

Concept Introduction: The given volume of matter contained in a material is termed as density. That is, density is the mass per unit volume of an object:

  $\text{Density =}\frac{\text{mass}}{\text{volume}}$

Answer to Problem 56A

Density in grams per cubic centimeter is $1.01\text{g}/{\text{cm}}^{\text{3}}$ .

Explanation of Solution

Given values are as follows:

  $\text{Volume}=1000{\text{cm}}^3$

Convert mass $1.01\text{kg}$ to g as follows:

  $\begin{array}{c}\text{Mass}=1.01\text{kg}\\ \text{=}1.01\text{kg}\times \frac{1000\text{g}}{1\text{kg}}\\ =1010\text{g}\end{array}$

Put above values in below equation.

  $\begin{array}{c}\text{Density =}\frac{\text{mass}}{\text{volume}}\\ =\frac{1010\text{g}}{1000{\text{cm}}^3}\\ =1.01\text{g}/{\text{cm}}^{\text{3}}\end{array}$

Hence, density is $1.01\text{g}/{\text{cm}}^{\text{3}}$ .

(d)

Interpretation Introduction

Interpretation: For the given values density in grams per cubic centimeter is needs to be calculate

Concept Introduction: The given volume of matter contained in a material is termed as density. That is, density is the mass per unit volume of an object:

  $\text{Density =}\frac{\text{mass}}{\text{volume}}$

Answer to Problem 56A

Density in grams per cubic centimeter is $0.90\text{g}/{\text{cm}}^{\text{3}}$ .

Explanation of Solution

Given values are as follows:

  $\begin{array}{c}\text{Volume}=2.51\text{mL}\\ \text{=}2.51{\text{cm}}^3\end{array}$

Since, $1\text{mL}=1{\text{cm}}^{\text{3}}$

  $\begin{array}{c}\text{Mass}=225\text{mg}\\ \text{=}225\text{mg}\times \frac{1\text{g}}{1000\text{mg}}\\ =0.225\text{g}\end{array}$

Put above values in below equation.

  $\begin{array}{c}\text{Density =}\frac{\text{mass}}{\text{volume}}\\ =\frac{0.225\text{g}}{2.51{\text{cm}}^3}\\ =0.90\text{g}/{\text{cm}}^{\text{3}}\end{array}$

Hence, density of the substance is $0.90\text{g}/{\text{cm}}^{\text{3}}$ .