Chapter 5, Problem 58A

Interpretation Introduction

Interpretation: For the given values density of the metals is needs to be calculated.

Concept Introduction: The given volume of matter contained in a material is termed as density. That is, it is the ratio of mass of an object to its volume:

  $\text{Density =}\frac{\text{mass}}{\text{volume}}$

Density increases with increase in volume of the substance.

Answer to Problem 58A

Density of the metal is $2.68\text{g}/{\text{cm}}^{\text{3}}$ .

Explanation of Solution

Given values are as follows:

  $\begin{array}{c}\text{Volume}=542\text{mL}\\ \text{=}542{\text{cm}}^3\end{array}$

Since, $1\text{mL}=1{\text{cm}}^{\text{3}}$

  $\begin{array}{c}\text{Mass}=1.45\text{kg}\\ \text{=}1.45\text{kg}\times \frac{1000\text{g}}{1\text{kg}}\\ =1450\text{g}\end{array}$

Substitute above values in below equation.

  $\begin{array}{c}\text{Density =}\frac{\text{mass}}{\text{volume}}\\ =\frac{1450\text{g}}{542{\text{cm}}^3}\\ =2.68\text{g}/{\text{cm}}^{\text{3}}\end{array}$

Hence, density is $2.68\text{g}/{\text{cm}}^{\text{3}}$ .

Conclusion

Density of the liquid is $2.68\text{g}/{\text{cm}}^{\text{3}}$ .