Root-mean-square thermal noise associated with a resister should be calculated. The fate of the thermal noise when the bandwidth is reduced to 100 Hz should be predicted. Concept introduction: Data given: Temperature (T) = Room temperature = 298 K Bandwidth ( Δ f ) = 1 MHz Resistance of the resistor (R) = 1.0 M Ω Thermal noise for a resistive circuit element can be given as υ ¯ r m s = 4 k T R Δ f Where, k = Boltzmann's constant = 1 .38 × 10 − 23 J/K T = Temperature in K R = Resistance in Ω Δ f = Bandwidth

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You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: xi 1. ☑ 2. H₂O хе i Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. There is no reagent that will make this synthesis work without complications. : ☐ S ☐

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Chapter 5, Problem 5.9QAP

Interpretation Introduction

Interpretation:

Root-mean-square thermal noise associated with a resister should be calculated. The fate of the thermal noise when the bandwidth is reduced to 100 Hz should be predicted.

Concept introduction:

Data given:

Temperature (T) = Room temperature = 298 K

Bandwidth ( Δf ) = 1 MHz

Resistance of the resistor (R) = 1.0 MΩ

Thermal noise for a resistive circuit element can be given as

υ¯rms=4kTRΔfWhere,k = Boltzmann's constant = 1.38×10−23 J/KT = Temperature in KR = Resistance in ΩΔf = Bandwidth

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