Chapter 5, Problem 57A

Interpretation Introduction

Interpretation: For the given values density of the liquid is needs to be calculated.

Concept Introduction: The given volume of matter contained in a material is termed as density. That is, density is mass per unit volume of an object to its volume:

  $\text{Density =}\frac{\text{mass}}{\text{volume}}$

Answer to Problem 57A

Density of the liquid is $0.84\text{g}/{\text{cm}}^{\text{3}}$ .

Explanation of Solution

Given values are as follows:

Since, $1\text{mL}=1{\text{cm}}^{\text{3}}$

  $\begin{array}{c}\text{Volume}=89.2\text{mL}\\ \text{=}89.2{\text{cm}}^3\\ \text{mass}=75.2\text{g}\end{array}$

Substitute above values in below equation.

  $\begin{array}{c}\text{Density =}\frac{\text{mass}}{\text{volume}}\\ =\frac{75.2\text{g}}{89.2{\text{cm}}^3}\\ =0.84\text{g}/{\text{cm}}^{\text{3}}\end{array}$

Hence, density is $0.84\text{g}/{\text{cm}}^{\text{3}}$ .

Conclusion

Density of the liquid is $0.84\text{g}/{\text{cm}}^{\text{3}}$ .