EBK THE COSMIC PERSPECTIVE
9th Edition
ISBN: 9780135161760
Author: Voit
Publisher: VST
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Chapter 5, Problem 53EAP
Electric Bill. Your electric utility bill probably shows your energy use for the month in units of kilowatt-hours. A kilowatt- hour is defined as the energy used in 1 hour at a rate of 1 kilowatt (1000 watts); that is,
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I have 72 lightbulbs in my house. 53 of these lightbulbs are 65 watt and the other 19 lightbulbs are 53 watt. I use the 65 watt lightbulbs an average of 10 hours a day and 53 watt an average of 12 hours a day. 1 kilowatt=1000 watts.
Estimate the energy used during 1 year by all the lightbulbs in my home?
A kilowatt-hour (kWh) is a unit of measure equal to one thousand watts of electricity being used in one hour. Power companies use this measurement to determine your home energy bill. Consider using a bike for power: It takes 6 minutes pedalling at 24-26 volts consistently to produce just 1/10 (0.1) of a kWh. An average home uses about 25 kWh a day. How long would someone have to pedal at 24-26 Volts to power an average home?
Explain the difference between energy and
power. Which unit of energy is used in your
electricity bill? If your daily electricity usage
on your bill had the number 9.1, what would
be your usage in SI units for the day? What
would your average power be for the day?
Chapter 5 Solutions
EBK THE COSMIC PERSPECTIVE
Ch. 5 - Prob. 1VSCCh. 5 - Prob. 2VSCCh. 5 - Prob. 3VSCCh. 5 - Prob. 4VSCCh. 5 - Prob. 5VSCCh. 5 - Prob. 1EAPCh. 5 - Prob. 2EAPCh. 5 - Why do we say that light is an...Ch. 5 - Prob. 4EAPCh. 5 - List the different forms of light in order from...
Ch. 5 - Prob. 6EAPCh. 5 - Prob. 7EAPCh. 5 - What is electrical charge? Will an electron and a...Ch. 5 - Describe the phase changes of water as you heat...Ch. 5 - Prob. 10EAPCh. 5 - Prob. 11EAPCh. 5 - Prob. 12EAPCh. 5 - Prob. 13EAPCh. 5 - Prob. 14EAPCh. 5 - Prob. 15EAPCh. 5 - Prob. 16EAPCh. 5 - Does It Make Sense? Decide whether the statement...Ch. 5 - Does It Make Sense? Decide whether the statement...Ch. 5 - Prob. 19EAPCh. 5 - Prob. 20EAPCh. 5 - Prob. 21EAPCh. 5 - Prob. 22EAPCh. 5 - Prob. 23EAPCh. 5 - Does It Make Sense? Decide whether the statement...Ch. 5 - Does It Make Sense? Decide whether the statement...Ch. 5 - Does It Make Sense? Decide whether the statement...Ch. 5 - Prob. 27EAPCh. 5 - Prob. 28EAPCh. 5 - Prob. 29EAPCh. 5 - Prob. 30EAPCh. 5 - Prob. 31EAPCh. 5 - Prob. 32EAPCh. 5 - Prob. 33EAPCh. 5 - Prob. 34EAPCh. 5 - Prob. 35EAPCh. 5 - Choose the best answer to each of the following....Ch. 5 - Prob. 39EAPCh. 5 - Prob. 40EAPCh. 5 - Prob. 41EAPCh. 5 - Prob. 42EAPCh. 5 - Prob. 43EAPCh. 5 - Atomic Terminology Practice II. What are the...Ch. 5 - Prob. 45EAPCh. 5 - Prob. 46EAPCh. 5 - Prob. 47EAPCh. 5 - Prob. 48EAPCh. 5 - Prob. 49EAPCh. 5 - Prob. 50EAPCh. 5 - Prob. 51EAPCh. 5 - Human Wattage. A typical adult uses about 2500...Ch. 5 - Electric Bill. Your electric utility bill probably...Ch. 5 - Prob. 54EAPCh. 5 - Prob. 55EAPCh. 5 - Prob. 56EAPCh. 5 - Prob. 57EAPCh. 5 - Prob. 58EAPCh. 5 - Prob. 59EAPCh. 5 - Prob. 60EAPCh. 5 - Prob. 61EAP
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- If the average household in a region consumes about 5,250 kWh of energy per year. In the region, the average annual solar energy potential is about 1,450 kWh/m² per year. If solar panels are available in sizes of 1 m x 1 m with an efficiency of 18 %, how many panels will be needed to power a house? (Since you can't have a fraction of panel, always round up you number to the next integer.) Your Answer: Answerarrow_forwardIn a sunny location, sunlight has a power density of about 1 kW/m2 . Photovoltaic solar cells can convert this power into electricity with 16% efficiency. If a typical home uses 390 kW⋅h of electricity per month, how many square meters of solar cells would be required to meet its energy requirements? Assume that electricity can be generated from the sunlight for 8 h/day .arrow_forwardOne kilowatt-hour (kWh) is the amount of work or energy generated when one kilowatt of power is supplied for one hour. A kilowatt-hour is the unit of energy used by power companies when figuring your electric bill. Determine the number of joules of energy in one kilowatt-hour.arrow_forward
- If you expended 1500 watts for 3 hours, how many kilowatt-hours (kWh) would that be? Enter answer as number followed by a space and then the correct units (i.e "123 Unit").arrow_forwardSuppose that you want to build a tower out of bricks. Suppose that each brick has a mass of 0.5 kg and is 0.1 m tall. You want the tower to be 20 bricks high, and we want to calculate how much energy is required to build it. The physics fact that you need is this: the energy, E (in Joules) required to lift a mass m (in kg) a height h (in m) is E = mgh (where g is the acceleration due to gravity - for this problem, you can take g to be 10 m/s2.) 1. We will assume that no energy is required to place the first brick in the tower, since it is already on the ground. What about the second brick? How high must if be lifted to be placed on top of the first brick? How much energy does that require? What about the third brick? The tenth brick?arrow_forwardA baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 1.5 kg. The carriage has Joules of energy. PLEASE USE COMMAS IN YOUR ANSWERS IF NEEDED! The formula for potential energy is: PE = mgh v = velocity or speed in m/s m = mass in kg g=10m/s (this is really 9.8 m/s on earth but we will use 10 for simplicity) h = height in metersarrow_forward
- The total consumption of electrical energy in the United States is about 1.0 1019 joules per year. What is the average rate of electrical energy consumption in watts? If the population of the United States is 300 million, what is the average rate of electrical energy consumption per person? The sun transfers energy to the earth by radiation at a rate of approximately 1.0 kW per square meter of surface. If this energy could be collected and converted to electrical energy with 40 % efficiency, how great an area (in square kilometers) would be required to collect the electrical energy used by the United States?arrow_forwardDon't skiparrow_forwardA new coal-burning power plant can generate 1:5 gigawatts (billion watts) of power. Burning 1 kilogram of coal yields about 449 kilowatt-hours of energy. Complete parts (a), (b), and (c) below. a. How much energy, in kilowatt-hours, can the plant generate each month? million kilowatt-hours of energy each month. The plant can generate (Type an integer.)arrow_forward
- A person consumes about 2600 Cal a day. 1 Cal = 4186 J, and 1 kWh = 860 Cal. What is this energy in kilowatt-hours? Express your answer using two significant figures.arrow_forwardA 181-kilogram object was pushed from rest to a speed of v meters per second, doing 22836.5 joules of work in the process. Find its speed. The speed of the car is -- meters per second. Note: Use g=9.81 m/s². Round off your answer to the second decimal place. Do not include the unit. Do not put commas in between digits. For numbers that are less than one, put a zero before the decimal point. For example, 0.56 and 0.123. From the previous item, A 181-kilogram object was pushed from rest to a speed of v meters per second, doing 22836.5 joules of work in the process. The car moves 9.4 meters during this time. Find the horizontal force exerted on the car. The horizontal force exerted on the car is -- newtons. Note: Use g=9.81 m/s2. Round off your answer to the second decimal place. Do not include the unit. Do not put commas in between digits. For numbers that are less than one, put a zero before the decimal point. For example, 0.56 and 0.123.arrow_forwardplease answer number 4arrow_forward
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