First Angle Length of opposite side: 5.25 cm Length of hypotenuse: 76 cm -1 5.25cm 76 cm = 0.0691340053 = 0.0691 Calculation of angle: 0 = sin¯ Mass of empty plastic beaker: 0.04485 kg Data Table 1: Activity 2, Part A: First Angle Trial Angle [degrees] Hanging mass Moving mass Calculated [kg] [kg] acceleration 1 3° 0.02746 kg 0.07231 kg 2 3° 0.02923 kg 0.07408 kg 3 3° 0.02924 kg 0.07409 kg (Equation 5) [ g(m² - m₁ sin 6) a= m₁ + m²

College Physics
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ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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Hello, please help with inputing trial one into the equation, I just need a model for the first one so I can answer the rest.  Also, does my data have the correct sigfig?

Thanks!

First Angle
Length of opposite side: 5.25 cm
Length of hypotenuse: 76 cm
-1
5.25cm
76 cm
= 0.0691340053 = 0.0691
Calculation of angle: 0 = sin¯
Mass of empty plastic beaker: 0.04485 kg
Data Table 1: Activity 2, Part A: First Angle
Trial
Angle [degrees] Hanging mass
Moving mass
Calculated
[kg]
[kg]
acceleration
1
3°
0.02746 kg
0.07231 kg
2
3°
0.02923 kg
0.07408 kg
3
3°
0.02924 kg
0.07409 kg
(Equation 5) [
g(m² - m₁ sin 6)
a=
m₁ + m²
Transcribed Image Text:First Angle Length of opposite side: 5.25 cm Length of hypotenuse: 76 cm -1 5.25cm 76 cm = 0.0691340053 = 0.0691 Calculation of angle: 0 = sin¯ Mass of empty plastic beaker: 0.04485 kg Data Table 1: Activity 2, Part A: First Angle Trial Angle [degrees] Hanging mass Moving mass Calculated [kg] [kg] acceleration 1 3° 0.02746 kg 0.07231 kg 2 3° 0.02923 kg 0.07408 kg 3 3° 0.02924 kg 0.07409 kg (Equation 5) [ g(m² - m₁ sin 6) a= m₁ + m²
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