Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 5, Problem 5.30P
To determine
The number of neutrons/s from 9Be(ϒ, n )8Be reaction.
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An aluminum foil of thickness 0.30 mm is bombarded by energetic neutrons. The
aluminum nuclei undergo neutron capture according to the process 2Al(n,y)28 Al, with
a measured capture cross section of 2.0×1031 m². Assuming the flux of incident
neutrons to be 5.0×10¹2 neutrons/ cm²-s, calculate the number of neutrons captured
per second by 1.0 cm² of the foil. The density of aluminum is 2.7 g/cm³.
A beam of α particles falls on 9Be nuclei. A resonance it is observed for an incidence energy of 1.732 MeV. a) Calculate the excitation energy ∆E of the corresponding state of the composite nucleus. b) The same state of resonance occurs in the collision of neutrons with 12C nuclei, Calculate the energy of the neutron beam in this resonance condition.
Answers: a) 11.85 MeV, b) 7.48 MeV.
Consider aCI nucleus to be a sphere with the seventeen protons uniformly distributed throughout.
(a) Determine the radius of this sphere (in m).
3k Q?
(b) If the energy needed to assemble a uniformly charged sphere of charge Q and radius R from separate charges is U = "e, determine the energy (in MeV) needed to assemble
5R
a uniformly charged sphere consisting of seventeen protons and with the radius determined in part (a).
|Mev
(c) Determine the binding energy (in MeV) for the nucleus CI. (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, and the mass of CI be 34.9689 u.)
MeV
Chapter 5 Solutions
Introduction To Health Physics
Ch. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10P
Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Calculate the probability that a 2-MeV photon in a...Ch. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - A 1-M solution of boric acid, H3BO3 , is...Ch. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.54PCh. 5 - What is the range in tissue of the beta particles...Ch. 5 - Prob. 5.56P
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- What is the dose in mSv for: (a) a 0.1 Gy xray? (b) 2.5 mGy of neutron exposure to the eye? (c) 1.5 mGy of exposure?arrow_forward(a) How many 239Pu nuclei must fission to produce a 20.0kT yield, assuming 200 MeV per fission? (b) What is the mass of this much 239Pu?arrow_forwardData from the appendices and the periodic table may be needed for these problems. A 60Co source is labeled 4.00 mCi, but its present activity is found to be 1.85107Bq. (a) What is the present activity in mCi? (b) How long ago did it actually have a 4.00—mCi activity?arrow_forward
- (a) Calculate the energy released in the neutroninduced fission (similar to the spontaneous fission in Example 32.3) n+238U96Sr+140Xe+3n, given m(96Sr)=95.921750u and m(140Xe)=139.92164. (b) This result is about 6 MeV greater than the result for spontaneous fission. Why? (c) Con?rm that the total number at nucleons and total charge are conserved in this reaction.arrow_forwardWhat is the dose in mSv for: (a) a 0.1-Gy X-ray? (b) 2.5 mGy of neutron exposure to the eye? (c) 1.5m Gy of a exposure?arrow_forward(a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forward
- (a) Background radiation due to 226Ra averages only 0.01 mSv/y, but it can range upward depending on where a 226Ra in the 80.0kg body of a man who receives a dose of 2.50mSv/y from it, noting that each 226Ra decay emits a 4.80MeV particle. You may person lives. Find the mass of neglect dose due to daughters and assume a constant amount, evenly distributed due to balanced ingestion and handily elimination. (b) Is it surprising that such a small mass could cause a measurable radiation dose? Explain.arrow_forwardTo determine the wear of an automobile engine, a steel compression ring is placed in a nuclear reactor, where it becomes neutron activated because of the formation of 59Fe(t1/2 = 44.5 days, β-). The activity of the ring when placed in the engine is 4.0 x 105 Bq. Over the next 60 days, the car is driven 100,000 km on a test track. The engine oil is extracted, and the activity rate of the oil is measured to be 512 β - /min. What fraction of the ring was worn off during the test?arrow_forwardA PuBe source has a neutron activity of 1.6 x 105 Bq. The neutrons are produced by the 9Be(∝ , n)12C reaction with an effective cross section of 90 mb and thickness of 3.2 cm. (a) What is the probability of an incident alpha particle interacting with a 9Be nucleus? (b) What must be the rate of alpha particles incident on 9Be? (c) What must be the amount of mass of the 239Pu producing the alpha particles?arrow_forward
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