Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 5, Problem 5.25P
To determine
The number of ion pairswhen beta particle is produced inside the tube.
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A living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5730 yr) for every 7.7 ✕ 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22O11) contains 21.1 mg of carbon. When the sample is placed inside a shielded beta counter with 88.0% counting efficiency, 769 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample.answer in year
Chapter 5 Solutions
Introduction To Health Physics
Ch. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10P
Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Calculate the probability that a 2-MeV photon in a...Ch. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - A 1-M solution of boric acid, H3BO3 , is...Ch. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.54PCh. 5 - What is the range in tissue of the beta particles...Ch. 5 - Prob. 5.56P
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- What is the dose in mSv for: (a) a 0.1 Gy xray? (b) 2.5 mGy of neutron exposure to the eye? (c) 1.5 mGy of exposure?arrow_forwardCalculate the dose in Sv to the chest at a patient given an xray under the following conditions. The xray beam intensity is 1.50 W/m2, the area of the chest exposed is 0.0750 m2 35.0% of the xrays are absorbed in 20.0 kg of tissue, and the exposure time is 0.250 s.arrow_forwardFind the radiation dose in Gy for: (a) A 10mSv fluoroscopic xray series. (b) 50 mSv of skin exposure by an emitter. (c) 160 mSv of and rays from the 40K in your body.arrow_forward
- (a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forwardWhat is the dose in Sv in a cancer treatment that exposes the patient to 200 Gy of rays?arrow_forwardA living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5 730 yr) for every 7.7 x 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22011) contains 30.0 mg of carbon. When the sample is placed inside a shielded beta counter with 86% counting efficiency, 833 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample in the nearest year (1 yr ~ 3.156 × 10' s).arrow_forward
- A 60-kg person accidentally ingests a small source of alpha particles ( RBE=15). The activity of the source is 0.04 Ci, the half-life of the source is 110 years, and each alpha particle emitted has an energy of 0.586 MeV. It takes 12hours for the alpha source to pass through the person's digestive system and exit the body. a). How many alpha particles are absorbed by the person ( assume that 100 percent of the alpha particles emitted by the source are absorbed by the person)? b). How many energy, in Joules, is deposited in the person by the source? c). What is the absorbed dose in rad? d). What is the absorbed dose in rem?arrow_forwardA living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5 730 yr) for every 7.7 × 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22O11) contains 21.0 mg of carbon. When the sample is placed inside a shielded beta counter, 837 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth’s atmosphere have not changed appreciably since the sample was formed, find the age of the sample. ( Atomic mass of C is 12u)arrow_forwardA 85 kg patient swallows a 31 μCi beta emitter with a half-life of 5.0 days, and the radioactive nuclei are quickly distributed throughout his body. The beta particles are emitted with an average energy of 0.35 MeV, 90% of which is absorbed by the body. What dose equivalent does the patient receive in the first week in mSv?arrow_forward
- radioisotope? is 1,000 counts per 14. Iodine-131, a beta emitter, has a half-life of 8 days. A 2-gram sample of initially pure iodine-131 is stored for 32 days. How much iodine- 131 remains in the sample afterward? 15. An accident in a laboratory results in a room being contaminated by a radioisotope with a half-life of 3 days. If the radiation is measured to be eight times the maximum permissible level, how much time must elapse before the room is safe to enter? 16. The amount of carbon-14 in an ancient wooden bowl is found to be one-half that in a new piece of wood. How old is the bowl? 17. When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. How many joules of energy were released by the explosion? 18. A nucleus of element 112 is formed using the reaction equation given near the end of Section 11.7. It then undergoes six successive alpha decays. Give the identity of the isotope that results after each step of this…arrow_forwardA living specimen in equilibrium with the atmosphere contains one atom of 14C (half- life = 5 730 yr) for every 7.7 x 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22011) contains 27 mg of carbon. When the sample is placed inside a shielded beta counter with 89% counting efficiency, 837 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample in the nearest year (1 yr ~ 3.1536 × 10' s). Take Avogadro Number to be DONT ROUND IN THE STEPS BECAUSE IT WILL NavG =6.026x1023 AFFECT YOUR ANSWER AND MAKE IT WRONGarrow_forwardA 60-kg person accidentally ingests a small source of alpha particles (RBE=15). The activity of the source is 0.04 Ci, the half-life of the source is 110 years, and each alpha particle emitted has an energy of 0.586 MeV. It takes 12hours for the alpha source to pass through the person’s digestive system and exit the body. (a) - How many alpha particles are absorbed by the person (assume that 100 percent of the alpha particles emitted by the source are absorbed by the person)? (b) - How much energy, in Joules, is deposited in the person by the source?arrow_forward
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