Chapter 5, Problem 5.26PE

(Compute e) You can approximate e using the following summation:

     $e=1+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\cdots +\frac{1}{i!}$

Write a program that displays the e value for i = 10000, 20000, ... , and 100000. (Hint: Because i! = i × (i − 1) ×… × 2 × 1, then

     $\frac{1}{i!}is\frac{1}{i\left(i-1\right)!}$

Initialize e and item to be 1, and keep adding a new item to e. The new item is the previous item divided by i, for i >= 2.)