Genetics: From Genes to Genomes, 5th edition
Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 5, Problem 51P

Two important methods for understanding the genetic basis for development are mitotic crossing-over and the use of the gene from jellyfish called GFP (for green fluorescent protein) that makes these animals glow in the dark. By recombinant DNA techniques described later in the book, you can insert the jellyfish GFP gene anywhere into the genome of organisms like Drosophila or mice. Cells expressing this GFP gene will glow green in the microscope, while those without the GFP gene will not glow green.

Mice homozygous for the recessive mutation small cells (smc) die as early embryos because their cells divide prematurely before they reach normal size.

You want to design a mouse carrying one copy of the GFP gene and heterozygous for smc in which you could generate clones in adult mice by mitotic recombination. In this designer mouse, every cell in every clone that is not green would be homozygous for the smc mutation. The figure below shows a field of epithelial cells in the mouse you design. You will see some cells that are normal size and other cells that are small. You will also see cells of three different colors: blank, weakly glowing cells (light green), and brightly glowing cells (dark green). Most of the cells in the epithelium of this mouse are of normal size and weakly glowing. The epithelium also contains three clones of cells (1, 2, and 3) that have unusual appearances due to the occurrence of mitotic recombination.

Chapter 5, Problem 51P, Two important methods for understanding the genetic basis for development are mitotic crossing-over

a. Show the chromosomes and centromeres, the alleles smc+ and smc, and GFP+ (GFP gene present) and GFP- (GFP gene absent) in your designer mouse. (As a reminder, this mouse will carry one copy of the GFP gene and will be heterozygous for smc. Every cell in every clone generated by mitotic recombination that is not green should
be homozygous for the smc mutation.)
b. Why do you need to use mitotic recombination to study the function of smc+ in adult mice?
c. Why do you see cells of three different colors?
d. Why are clones 1 and 2 next to each other?
e. On your map in part (a), place an arrow to show the position of a mitotic recombination event that could give rise to clones 1 and 2.
f. Why are there more cells exist in clone 1 than in clone 2?
g. On your map in part (a), place an arrow to show the position of a mitotic recombination event that could give rise to clone 3.
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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.)   Data Table 1Stage    Totals    PercentInterphase        Mitosis:        Prophase        Metaphase        Anaphase        Telophase        Cytokinesis        Totals    100    100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…
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Chapter 5 Solutions

Genetics: From Genes to Genomes, 5th edition

Ch. 5 - Albino rabbits lacking pigment are homozygous for...Ch. 5 - In corn, the allele A allows the deposition of...Ch. 5 - If the a and b loci are 40 cM apart and an AA BB...Ch. 5 - Write the number of different kinds of phenotypes,...Ch. 5 - A DNA variant has been found linked to a rare...Ch. 5 - Figure 5.7a on p. 134 shows chromosomes during...Ch. 5 - Figure 5.7b shows bivalents in mouse primary...Ch. 5 - Cinnabar eyes cn and reduced bristles rd are...Ch. 5 - In Drosophila, the autosomal recessive dp allele...Ch. 5 - From a series of two-point crosses, the following...Ch. 5 - Map distances were determined for four different...Ch. 5 - In the tubular flowers of foxgloves, wild-type...Ch. 5 - In Drosophila, the recessive allele mb of one gene...Ch. 5 - A snapdragon with pink petals, black anthers, and...Ch. 5 - In Drosophila, three autosomal genes have the...Ch. 5 - Drosophila females heterozygous for each of three...Ch. 5 - Male Drosophila expressing the autosomal recessive...Ch. 5 - a. In Drosophila, crosses between F1 heterozygotes...Ch. 5 - A true-breeding strain of Virginia tobacco has...Ch. 5 - Prob. 30PCh. 5 - The following list of four Drosophila mutations...Ch. 5 - Do the data that Mendel obtained fit his...Ch. 5 - Two genes control color in corn snakes as follows:...Ch. 5 - A mouse from a true-breeding population with...Ch. 5 - Neurospora of genotype a c are crossed with...Ch. 5 - A cross was performed between one haploid strain...Ch. 5 - A cross was performed between a yeast strain that...Ch. 5 - Two crosses were made in Neurospora involving the...Ch. 5 - Indicate the percentage of tetrads that would have...Ch. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - a. In ordered tetrad analysis, what is the maximum...Ch. 5 - A research group has selected three independent...Ch. 5 - A single yeast cell placed on a solid agar will...Ch. 5 - Prob. 48PCh. 5 - In Drosophila, the yellow y gene is near the end...Ch. 5 - Neurofibromas are tumors of the skin that can...Ch. 5 - Two important methods for understanding the...
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