COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 5, Problem 42QAP
To determine
In this problem we have to determine mass of the object.
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The leg bone (femur) breaks under a compressive force of about 6.50 × 104 N for a human and 12.3 × 104 N for a horse.
The human femur has a compressive strength of 160 MPa, whereas the horse femur has a compressive strength of 140
MPa.
What is the effective cross-sectional area of the femur in a horse? (Note: Since the center of the femur contains bone marrow, which
has essentially no compressive strength, the effective cross-sectional area is about 80% of the total cross-sectional area.)
cm2
no ai please
A block of mass m₁ = 1.85 kg and a block of mass m₂
is 0.360 for both blocks.
=
m
M, R
m2
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5.90 kg are connected by a massless string over a pulley in the shape of a solid disk having a mass of M = 10.0 kg. The fixed, wedge-shaped ramp makes an angle of 0 = 30.0° as shown in the figure. The coefficient of kinetic friction
(a) Determine the acceleration of the two blocks. (Enter the magnitude of the acceleration.)
x m/s²
(b) Determine the tensions in the string on both sides of the pulley.
left of the pulley
× N
right of the pulley
X N
Enter a number.
Chapter 5 Solutions
COLLEGE PHYSICS
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