(a)
Interpretation:
Interpret name of NaMnO4.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(b)
Interpretation:
Interpret name of AlPO4.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(c)
Interpretation:
Interpret name of CrCO3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(d)
Interpretation:
Interpret name of Ca(ClO2 )2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(e)
Interpretation:
Interpret name of BaCO3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(f)
Interpretation:
Interpret name of CaCrO4.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

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Chapter 5 Solutions
Introductory Chemistry: Foundation - Text (Looseleaf)
- Select the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forwardb. H3C CH3 H3O+ ✓ H OHarrow_forward
- 2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forwardIdentify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forward
- Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forwardC. NaOMe, Br Brarrow_forward
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