(a)
Interpretation:
Interpret name of ionic substance with charge specifying by roman number for SnCl2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
(b)
Interpretation:
Interpret name of ionic substance with charge specifying by roman number for Fe2 S3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
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Chapter 5 Solutions
Introductory Chemistry: Foundation - Text (Looseleaf)
- The number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forwardNonearrow_forwardThe number of carbon skeletons that have 8 carbons, one of which istertiary is A. 7; B. More than 7; C. 6; D. 5; E. 4arrow_forward
- The azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forwardThe sum of the numerals in the name of the compoundis A. None of the other answers is correct.; B. 11;C. 6; D. 8; E. 5.arrow_forwardA compound has a six carbon ring with three double bonds. Attachedto the ring is a three carbon chain with a triple bond and a two carbonchain with two bromines attached. The number of hydrogens in a molecule of this compound is A. 10; B. 12; C. 14; D. 13; E. None of the other answers is correct.arrow_forward
- Can you help me? I can't seem to understand the handwriting for the five problems, and I want to be able to solve them and practice. If you'd like to give me steps, please do so to make it easier understand.arrow_forwardThe number of 2sp3 hybrid orbitals in the moleculeis A. 12; B. 8; C. 3; D. 11; E. None of the other answers is correct.arrow_forwardNonearrow_forward
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