Explain how σ and
Interpretation:
The similarity and difference between s and p bonds is to be explained.
Concept Introduction:
- There are two types of bonds that are formed between the atoms-
- Electron in atoms occupy atomic orbitals while in molecule, electrons occupy molecular orbitals. These molecular orbitals are formed by the combination of the atomic orbitals and they can be bonding molecular orbitals and ant-bonding molecular orbitals.
- The process of mixing of atomic orbitals of similar energy to produce new molecular orbitals of equivalent energy is known as hybridization.
a) Covalent bond- the bond formed by the sharing of electrons between the atoms.
b) Ionic bond- When atoms gain/loss electrons and become ions, the electrostatic attraction between the oppositely charged ions is known as ionic bond.
Answer to Problem 1E
Similarity-They both are chemical covalent bonds and are formed by the overlapping of the atomic orbitals.
Differences-
s- bond | ?-bond |
Formed by the axial overlap of the atomic orbitals. | Formed by the side-ways overlap of the atomic orbitals. |
It can be formed by the overlap of s-s, s-p or p-p orbitals. | It can only be formed by the overlap of p orbitals |
Oriented along the internuclear axis. | Oriented perpendicular to the internuclear axis. |
Exists independently. | Exist along with sigma bond. |
Stronger than pi-bond. | Weaker than sigma bond. |
More reactive. | Less reactive. |
Determines the shape of the molecule. | Does not determine the shape of the molecule. |
Explanation of Solution
- Sigma (s) bonds- It is a type of covalent bond which is formed by the end to end overlapping of the atomic orbitals of the atoms involved in bonding.
- Pi (p)bonds -It is a type of covalent bond which is formed by the side wise overlapping of the atomic orbitals of the atoms involved in bonding.
Therefore, differences between sigma and pi bonds are-
s- bond | ?-bond |
Formed by the axial overlap of the atomic orbitals. | Formed by the side-ways overlap of the atomic orbitals. |
It can be formed by the overlap of s-s, s-p or p-p orbitals. | It can only be formed by the overlap of p orbitals |
Oriented along the internuclear axis. | Oriented perpendicular to the internuclear axis. |
Exists independently. | Exist along with sigma bond. |
Stronger than pi-bond. | Weaker than sigma bond. |
More reactive. | Less reactive. |
Determines the shape of the molecule. | Does not determine the shape of the molecule. |
However, the only similarity between these two are that they both are chemical covalent bonds and are formed by the overlapping the atomic orbitals, and the main difference is that sigma bond is formed by the axial overlap of the atomic orbitals, whereas, pi bond is formed by the sideways overlapping of atomic orbitals.
Want to see more full solutions like this?
Chapter 5 Solutions
Chemistry Atoms First2e
- a Nitrogen trifluoride, NF3, is a relatively unreactive, colorless gas. How would you describe the bonding in the NF3 molecule in terms of valence bond theory? Use hybrid orbitals. b Silicon tetrafluoride, SiF4, is a colorless gas formed when hydrofluoric acid attacks silica (SiO2) or glass. Describe the bonding in the SiF4 molecule, using valence bond theory.arrow_forwardDefine Compounds Containing C–Z σ Bonds ?arrow_forwardIf the subscripts g and u stand for unbonded and bonded, respectively. Why does 1pi u appear before 1pi g in the molecular orbital diagrams of O2 and N2?arrow_forward
- VISUALIZATION Energy Diagram for Conversion of Cis-2-Butene to Trans-2-Butene 600 500 400 Reactant 300 200 E = 435 x 1021 J 100 Initial state AE-7 X 10 J -30° 30 60 90° 120° 150° 180° 210° Reaction progress (angle of twist) Cis-2-butene is one of two forms of butene where the middle two carbon atoms are joined by a double bond. The other form is trans-2-butene. The conversion of the cis form to the trans form is slow at room temperature, and the two forms represent two distinct compounds. Conversion of the cis to the trans form involves rotation about the C-C double bond, which requires a substantial amount of energy on the molecular scale. Move the slider to observe the different conformations and their energies along the pathway of the conversion. Potential Energy 1021 Jarrow_forward3 2 4 5 Consider the following second-period heteronuclear diatomic molecule. Combining the valence orbitals (2px, 2py, 2pz, and 2s) of each of the two atoms creates eight new orbitals (one 02s*, one 02s, one 02p, one 02p, two л₂p, and two л₂p) that span the entire molecule and explain it's electronic properties. Those eight new orbitals exist at six energy levels. Rank the molecular orbitals of a F2 molecule from lowest (1) to highest (6) energy. Fatom 6- highest 1- lowest F2 molecule [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] F atomarrow_forwardExplain the Conversion of RCOOH to RCONR′2arrow_forward
- Construct the molecular orbital diagram for SrCl. Would yo u expect the bond length of SrCl+ to be longer or shorter than that of SrCl? Explain and elaborate.arrow_forwardBelow is an incomplete molecular orbital diagram. Fill in the diagram for the diatomic molecule X2, where each atom of X has 6 valence electrons in s and p orbitals. w р S π р S Based on your diagram, [Select] substance would be expected to be [Select] bond(s) would be expected to form and the ?arrow_forwardUse the molecular orbital model to fully describe the bonding in O2+, O2, O2-, and O22-.Determine which of the following statements are true and which are false. True or false? : Bond length increases with increasing bond order while bond energy decreases.The number of unpaired electrons in O2- and O2 is, respectively, 1 and 2. The electron configuration of O2 is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)1. The electron configuration of O2- is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)3. The bond order in O2- and O22- is, respectively, 2.5 and 1. The bond lengths increase in the order: O22- < O2- < O2 < O2+.arrow_forward
- What is the electron configuration of the Br2+molecular ion? Is its bond stronger or weaker than that in Br2? What is its bond order?arrow_forwardThe average bond energy (enthalpy) for a C=C double bond is 614 kJ/molkJ/mol and that of a C−C single bond is 348 kJ/molkJ/mol. If it takes 4.42×10−19 J/molecule to break the C=C double bond. What is the longest wavelength λ of light that will provide photons of sufficient energy to break the π bond and cause the isomerization? Express your answer numerically in nanometers.arrow_forwardWhat are the relative lengths and strengths of the carbon–halogen bonds in CH3F, CH3Cl, and CH3Br?arrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning