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Concept explainers
Interpretation:
The difference between alpha and beta glucose is to be found out.
Concept introduction:
Glucose can form either five-membered or six-membered rings. The six-membered ring is much more common, and in solution the vast majority of glucose molecules are found to have six-membered rings.
Each molecule of glucose has a carbon backbone with -OH groups and hydrogen atoms attached to it. At the top of the chain, an oxygen atom is double-bonded to a carbon atom; collectively, these two atoms are called a carbonyl group. The carbon backbone of the glucose molecule can coil up so that an -OH group near the bottom end of the chain attacks the carbonyl carbon and the glucose molecule forms a ring. This ring-shaped structure is the cyclic form of glucose, while the straight chain structure is the linear form.
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Chapter 4 Solutions
Organic Chemistry
- Nonearrow_forwardman Campus Depa (a) Draw the three products (constitutional isomers) obtained when 2-methyl-3-hexene reacts with water and a trace of H2SO4. Hint: one product forms as the result of a 1,2-hydride shift. (1.5 pts) This is the acid-catalyzed alkene hydration reaction.arrow_forwardNonearrow_forward
- H HgSO4, H2O H2SO4arrow_forward12. Choose the best diene and dienophile pair that would react the fastest. CN CN CO₂Et -CO₂Et .CO₂Et H3CO CO₂Et A B C D E Farrow_forward(6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forward
- Nonearrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception to the general ionization energy (IE) trend. For the two elements involved, answer the following questions. Be sure to cite sources for all physical data that you use. a. (2 pts) Identify the two elements and write their electronic configurations. b. (2 pts) Based on their configurations, propose a reason for the IE trend exception. c. (5 pts) Calculate effective nuclear charges for the last electron in each element and the Allred-Rochow electronegativity values for the two elements. Can any of these values explain the IE trend exception? Explain how (not) - include a description of how IE relates to electronegativity.arrow_forwardPlease explain thoroughly and provide steps to draw.arrow_forward
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- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
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