Concept explainers
Interpretation:
The difference between alpha and beta glucose is to be found out.
Concept introduction:
Glucose can form either five-membered or six-membered rings. The six-membered ring is much more common, and in solution the vast majority of glucose molecules are found to have six-membered rings.
Each molecule of glucose has a carbon backbone with -OH groups and hydrogen atoms attached to it. At the top of the chain, an oxygen atom is double-bonded to a carbon atom; collectively, these two atoms are called a carbonyl group. The carbon backbone of the glucose molecule can coil up so that an -OH group near the bottom end of the chain attacks the carbonyl carbon and the glucose molecule forms a ring. This ring-shaped structure is the cyclic form of glucose, while the straight chain structure is the linear form.
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Chapter 4 Solutions
Organic Chemistry
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- The following are representations of two forms of glucose. The six-membered ring is known to exist in a chair conformation in each form. Draw clear representations of the most stable conformation of each. Are they two different conformations of the same molecule, or are they stereoisomers that cannot be interconverted by rotation about single bonds? Which substituents (if any) occupy axial sites?arrow_forwardIntramolecular H-bonding (IHB) are interactions that occur within one single molecule. IHB is also known as chelation, since it involves ring formation. Which of the following is (are) stabilized by IHB? * QH Çi OH -NO2 (a) Cl-Ç–Ç–H (b) či ÓH OH (с) CH, —С—СH—С—ОС,Н, CH,OH (d) | CH,OH D B Aarrow_forwardPlease answer all of it. If not, please skip. Draw the structure of a branched hydrocarbon that also contains at least one atom with trigonal planar geometry. Draw the structure of an aromatic hydrocarbon containing two halogens. Draw the structure of a molecule containing an aliphatic primary amine and a carboxyl group. Draw the structure of an acyclic molecule containing a primary and a secondary alcohol group. Draw the structure of an achiral tertiary alcoholarrow_forward
- For rotation about the C-a – C-b bond, using the following templates, draw the Newman Projection of the two staggered conformers that are different in energy. Fill each bond on Newman Projection with Hydrogen or Substituents. You may use Abbreviations such as Me for Methyl, Et for Ethyl, iPr for isopropyl. Circle the Newman projection of the most stable conformer.arrow_forward2arrow_forwardClassifying Compounds as Stereoisomers or Different Conformations Classify each pair of compounds as stereoisomers or conformations: (a) X and Y; (b) X and Z.arrow_forward
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