Number of molecules of water in glass of water (235 g) should be identified. Concept Introduction: Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows: n=m /M. where, n is mol. m is mass in g. M is molar mass.

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#30 problem B

Answer 1

Question

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

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#30 problem B

PROBLEM-SOLVING EXAMPLE 3-6 Percent Composition of Hydrated Salt Epsom salt is MgSO, 7 H,O. (a) What is the percent by mass of water in Epsom salt? (b) What are the percentages of each element in Epsom salt? Strategy and Explanation a. We first find the molar mass of Epsom salt, which is the sum of the molar masses of the atoms in the chemical formula: [1 mol Mg x (24.31 g Mg/mol Mg)] + [1 mol S x (32.07 g S/mol S)] + [4 mol O x (15.9994 g O/mol O)] + [14 mol H x (1.0079 g H/mol H)] + [7 mol O x (15.9994 g O/mol O)] = 246.49 g/mol Epsom salt Because 1 mol Epsom salt contains 7 mol H,O, the mass of water in 1 mol Epsom salt is, 7 mol H,O x (18.012 g H,O/mol H,O) = 126.08 g H,0 126.08 g water per mol Epsom salt % H,O = x 100% = 51.15% H,O %3D 246.49 g/mol Epsom salt b. We calculate the percentage of magnesium from the ratio of the mass of magnesium in 1 mol Epsom salt to the mass of Epsom salt in 1 mol: mass of Mg in 1 mol Epsom salt % Mg mass of Epsom salt in 1 mol 24.31g Mg x 100% =…

PROBLEM-SOLVING PRACTICE 3-6 What is the mass percent of each element in hydrated nickel(II) chloride, NiCl, 6 H.02

Answer 2

Question

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

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Answer 3

Question

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

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Answer 4

Question

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

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Answer 5

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

Answer 6

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

Answer 7

Chapter 4.6, Problem 4.11P

Interpretation Introduction

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

Answer 8

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Ch. 4.2 - Problem 4-1 Following is an unbalanced equation...Ch. 4.2 - Problem 4-2 Balance this equation:Ch. 4.2 - Prob. 4.3P Ch. 4.3 - Problem 4-4 When a solution of copper(II)...Ch. 4.4 - Problem 4-5 In each equation, identify the...Ch. 4.5 - Problem 4-6 What is (a) the molecular weight of...Ch. 4.6 - Prob. 4.7P Ch. 4.6 - Problem 4-8 We wish to weigh 2.84 mol of sodium...Ch. 4.6 - Problem 4-9 How many moles of C atoms, H atoms,...Ch. 4.6 - Problem 4-10 How many moles of copper(I) ions,...

Number of molecules of water in glass of water (235 g) should be identified. Concept Introduction: Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows: n=m /M. where, n is mol. m is mass in g. M is molar mass.

Solution Summary: The author explains the molecular formula of water, which is H 2 O. The number of molecules in water (235 g) should be identified.

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.

Chapter 4 Solutions

Number of molecules of water in glass of water (235 g) should be identified. Concept Introduction: Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows: n=m /M. where, n is mol. m is mass in g. M is molar mass.

Solution Summary: The author explains the molecular formula of water, which is H 2 O. The number of molecules in water (235 g) should be identified.

Interpretation: Number of molecules of water in glass of water (235 g) should be identified. Concept Introduction: Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows: n=m /M. where, n is mol. m is mass in g. M is molar mass.

Chapter 4 Solutions

Interpretation:

Number of molecules of water in glass of water (235 g) should be identified.

Concept Introduction:

Number of mol of a compound can be determined by dividing the mass of compound in g by its molar mass as follows:

n=m /M.

where, n is mol.

m is mass in g.

M is molar mass.