Chapter 4.5, Problem 25PPE

To determine

To write: A function that can represent whale’s depth as function of time and calculate the whale’s depth at 4 min.

Answer to Problem 25PPE

Whale’s depth at 4 min will be 10.7 m and function for whale’s depth is $d\left(t\right)=3.5+1.8t$

Explanation of Solution

Given information:

From initial elevation of 3.5 m below the surface of the water, a northern bottlenose whale drives at rate of 1.8 m/s.

Calculation:

Whale’s depth at any time = d.

Initial elevation = 3.5 m.

Dive rate = 1.8 m/s

Therefore depth can be written as function of t (in min) as follows:

  $d\left(t\right)=3.5+1.8t$

Using above function the height of helicopter at 4 minutes will be

  $\begin{array}{c}d\left(4\right)=3.5+1.8\times 4\\ =3.5+7.2\\ =10.7\end{array}$