Cellphone Revenues The annual revenue for cellphone use in China for the period 2000–2005 was projected to follow the equation 60 R ( t ) = 14 t + 24 billon dollars inyear t . ( t = 0 represents2000.) At the same time, there were approximately 68 million subscribers in 2000. Assuming that the number of subscribers increases exponentially with an annual growth constant of 10%, give a formula for the annual revenue per subscriber in year t . Hence, project to the nearest dollar the annual revenue per subscriber and its rate of change in 2002. (Be careful with units!)
Cellphone Revenues The annual revenue for cellphone use in China for the period 2000–2005 was projected to follow the equation 60 R ( t ) = 14 t + 24 billon dollars inyear t . ( t = 0 represents2000.) At the same time, there were approximately 68 million subscribers in 2000. Assuming that the number of subscribers increases exponentially with an annual growth constant of 10%, give a formula for the annual revenue per subscriber in year t . Hence, project to the nearest dollar the annual revenue per subscriber and its rate of change in 2002. (Be careful with units!)
Solution Summary: The author calculates the formula for the annual revenue per subscriber in year t and the rate of change in 2002.
Cellphone Revenues The annual revenue for cellphone use in China for the period 2000–2005 was projected to follow the equation60
R
(
t
)
=
14
t
+
24
billon dollars
inyear t. (
t
=
0
represents2000.) At the same time, there were approximately 68 million subscribers in 2000. Assuming that the number of subscribers increases exponentially with an annual growth constant of 10%, give a formula for the annual revenue per subscriber in year t. Hence, project to the nearest dollar the annual revenue per subscriber and its rate of change in 2002. (Be careful with units!)
x
The function f is shown below. If I is the function defined by g(x) = √ ƒ(t) dt, find the value of g"(-8) in simplest form.
g
-1
8
y
7
10
6
LC
5
4
3 2
1
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1
1
2
3
-1
-2
-3
-4
-5
56
-6
-7
-8
4 5
Graph of f
10
6
00
7 8
9 10
x
The function f is shown below. If g is an antiderivative of f such that g(6) = 2, what is the maximum value of g on the closed interval
[-9,9]?
8
7
6
Сл
5
4
3
1
y
Graph of f
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1
1
23 4
-1
-2
-3
-4
-6
56
-5
-7
-8
LO
5
9
7
8
9
10
x
The function of is shown below. If I is the function defined by g(x) = [* f(t)dt, write the equation of the line tangent to the graph of 9
at x = -3.
g
y
Graph of f
8
7
6
5
4
32
1
x
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1
1
2
3 4
5
6
7
8
9 10
-1
-2
-3
56
-6
-7
-8
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