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Determine the moment of each of the three forces about point B.
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Chapter 4 Solutions
Engineering Mechanics: Statics Plus Mastering Engineering with Pearson eText -- Access Card Package (14th Edition) (Hibbeler, The Engineering Mechanics: Statics & Dynamics Series, 14th Edition)
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- The differential equation of a cruise control system is provided by the following equation: WRITE OUT SOLUTION DO NOT USE A COPIED SOLUTION Find the closed loop transfer function with respect to the reference velocity (vr) . a. Find the poles of the closed loop transfer function for different values of K. How does the poles move as you change K? b. Find the step response for different values of K and plot in MATLAB. What can you observe?arrow_forwardSolve this problem and show all of the workarrow_forwardDetermine the minimum applied force P required to move wedge A to the right. The spring is compressed a distance of 175 mm. Neglect the weight of A and B. The coefficient of static friction for all contacting surface is μs = 0.35. Neglect friction at the rollers. k = = 15 kN/m P A B 10°arrow_forward
- DO NOT COPY SOLUTION- will report The differential equation of a cruise control system is provided by the following equation: Find the closed loop transfer function with respect to the reference velocity (vr) . a. Find the poles of the closed loop transfer function for different values of K. How does the poles move as you change K? b. Find the step response for different values of K and plot in MATLAB. What can you observe?arrow_forwarda box shaped barge 37m long, 6.4 m beam, floats at an even keel draught of 2.5 m in water density 1.025 kg/m3. If a mass is added and the vessel moves into water density 1000 kg/m3, determine the magnitude of this mass if the fore end and aft end draughts are 2.4m and 3.8m respectively.arrow_forwarda ship 125m long and 17.5m beam floats in seawater of 1.025 t/m3 at a draught of 8m. the waterplane coefficient is 0.83, block coefficient 0.759 and midship section area coefficient 0.98. calculate i) prismatic coefficient ii) TPC iii) change in mean draught if the vessel moves into water of 1.016 t/m3arrow_forward
- c. For the given transfer function, find tp, ts, tr, Mp . Plot the resulting step response. G(s) = 40/(s^2 + 4s + 40) handplot only, and solve for eacharrow_forwardA ship of 9000 tonne displacement floats in fresh water of 1.000 t/m3 at a draught 50 mm below the sea water line. The waterplane area is 1650 m2. Calculate the mass of cargo which must be added so that when entering seawater of 1.025 t/m3 it floats at the seawater line.arrow_forwardA ship of 15000 tonne displacement floats at a draught of 7 metres in water of 1.000t/cub. Metre.It is required to load the maximum amount of oil to give the ship a draught of 7.0 metre in seawater ofdensity 1.025 t/cub.metre. If the waterplane area is 2150 square metre, calculate the massof oil requiredarrow_forward
- A ship of 8000 tonne displacement floats in seawater of 1.025 t/m3 and has a TPC of 14. The vessel moves into fresh water of 1.000 t/m3 and loads 300 tonne of oil fuel. Calculate the change in mean draught.arrow_forwardAuto Controls DONT COPY ANSWERS - will report Perform the partial fraction expansion of the following transfer function and find the impulse response: G(s) = (s/2 + 5/3) / (s^2 + 4s + 6) G(s) =( 6s^2 + 50) / (s+3)(s^2 +4)arrow_forwardI submitted the below question and received the answer i copied into this question as well. Im unsure if it is correct, so looking for a checkover. i am stuck on the part tan-1 (0.05) = 0.04996 radians. Just unsure where the value for the radians came from. Just need to know how they got that answer and how it is correct before moving on to the next part. If any of the below information is wrong, please feel free to give me a new answer or an entire new explanation. An Inclining experiment done on a ship thats 6500 t, a mass of 30t was moved 6.0 m transvesly causing a 30 cm deflection in a 6m pendulum, calculate the transverse meta centre height. Here is the step-by-step explanation: Given: Displacement of the ship (W) = 6500 tonnes = 6500×1000=6,500,000kg Mass moved transversely (w) = 30 tonnes=30×1000=30,000kg The transverse shift of mass (d) = 6.0 meters Pendulum length (L) = 6.0 meters Pendulum deflection (x) = 30 cm = 0.30 meters Step 1: Formula for Metacentric Height…arrow_forward
- International Edition---engineering Mechanics: St...Mechanical EngineeringISBN:9781305501607Author:Andrew Pytel And Jaan KiusalaasPublisher:CENGAGE L
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