Chapter 4.3, Problem 4.10BFP

Interpretation Introduction

Interpretation:

The molarity of a silver nitrate solution if $45.0\text{ mL}$ of it reacts with excess sodium chloride to produce $0.148\text{ g}$ of precipitate is to be determined.

Concept introduction:

Precipitation reaction involves the reaction of two soluble ionic compounds to form an insoluble product. The insoluble product is known as a precipitate.

The reason for the precipitation reaction to occur is the formation of a product that is insoluble in nature. For example, silver nitrate and sodium chloride react to precipitate out silver chloride.

${\text{AgNO}}_3\left(aq\right)+\text{NaCl}\left(aq\right)\to \text{AgCl}\left(s\right)+{\text{NaNO}}_3\left(aq\right)$