Chapter 4.1, Problem 4.4BFP

Interpretation Introduction

Interpretation:

Moles of sulphuric acid present in $40.5\text{ mL}$ of a $0.128M$ solution of sulfuric acid are to be calculated.

Concept introduction:

Molarity $\left(M\right)$ is one of the concentration terms that determine the number of moles of solute present in per liter of solution. Unit of molarity is $\text{mol}/\text{L}$.

The expression to calculate the amount of compound in moles when molarity of solution and volume of solution is given is as follows:

$\text{moles of solute}\left(\text{mol}\right)=\left(\text{volume of solution}\left(\text{L}\right)\right)\left(\frac{\text{molarity of solution}\left(\text{mol}\right)}{\text{1}\text{L of solution}}\right)$