Chapter 4.2, Problem 43E

To determine

To Find: The cost of 3.2 GHz computer system.

Answer to Problem 43E

The cost of the 400 MHz computer system is $\$643$ .

Explanation of Solution

Given:

The computer factory sells 2.4 GHz computer system for $595 and 2.8GHz for $619.

Calculation:

Consider that the computer factor is selling a 300 MHz computer system of $595 and 350 MHz system for $619.

Consider $x$ is the MHz of the computer and the cost of is represented by $y$ .

Then, the linear relation between x and y is the equation of the line that passes through the point $\left(300,595\right)$ and $\left(350,619\right)$ .

Then, the equation of the line is,

  $\begin{array}{c}y-595=\frac{619-595}{350-300}\left(x-300\right)\\ =0.48x-144+595\\ =0.48x+451\end{array}$

Then, the cost of 400 MHz is obtained by the substitution $x=400$ in the equation as,

  $\begin{array}{c}y=0.48\left(400\right)+451\\ =\$643\end{array}$

Then, the cost of the 400 MHz computer system is $\$643$ .