Chapter 4.2, Problem 28E

To determine

To solve: $3s^2-5s+9=0$

Answer to Problem 28E

  $x=\frac{5+i\sqrt{83}}{6}\text{ or }x=\frac{5-i\sqrt{83}}{6}$

Explanation of Solution

Given information: $3s^2-5s+9=0$

Calculation:

Given

  $3s^2-5s+9=0$

Discriminant,

  $b^2-4ac={\left(5\right)}^2-4\ast 3\left(9\right)=25-108=-83$

Quadratic formula

  $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute values

  $\begin{array}{l}x=\frac{5\pm \sqrt{-83}}{6}\\ x=\frac{5\pm i\sqrt{83}}{6}\\ x=\frac{5+i\sqrt{83}}{6}\text{ or }x=\frac{5-i\sqrt{83}}{6}\end{array}$