Chapter 4.1, Problem 48E

To determine

To solve: $\left(u+1\right)\left(u^2-1\right)=0$ and graph the related polynomial function.

Answer to Problem 48E

  $u=-1\text{ and }1$

  

Explanation of Solution

Given information: Solve $\left(u+1\right)\left(u^2-1\right)=0$ and graph the related polynomial function

Calculation:

  $\left(u+1\right)\left(u^2-1\right)=0$

By solving for u

  $\begin{array}{l}\left(u+1\right)\left(u^2-1\right)=0\\ u+1=0\\ u=-1\\ u^2-1=0\\ u^2=1\\ u=-1,1\end{array}$

We get $u=-1\text{ and }1$

The graph