Chapter 4.1, Problem 41E

To determine

To state: the number of complex roots of $b^2+36=0$ and then find the roots and graph.

Answer to Problem 41E

There are 2 complex roots, both are purely imaginary: $0+6i,0-6i$ .

  

Explanation of Solution

Given information: $b^2+36=0$

Calculation:

  $\begin{array}{l}{b}^2+36=0\\ b^2=-36\\ b=\pm 6i\end{array}$

This means there are 2 complex roots, and both are purely imaginary: $0+6i,0-6i$

The graph