MASTERINGPHYSICS W/ETEXT ACCESS CODE 6
13th Edition
ISBN: 9781269542661
Author: YOUNG
Publisher: PEARSON C
expand_more
expand_more
format_list_bulleted
Question
Chapter 42, Problem 42.24E
To determine
The probability that a state with energy
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The Boltzmann constant is k = 8.617 * 10-5 eV/K. For a metallic solid at room temperature (293 K), what is the probability that an electron state is occupied if its energy is 0.100 eV above the Fermi level?
Plot the Fermi function Vs. Energy at the temperature of 500 K, when EF = 2 eV
The 2DEG in (iii) is patterned to produce a clean, quasi-1D channel. The current I through
the channel is =
Nev, where N =
the number of electrons, e
the electronic charge and
= the electrons' group velocity. The number of electrons N(ɛ) = f(ɛ, µ)g(ɛ), where
f (ɛ, u) =Fermi-Dirac distribution =
1
and g(ɛ)
density of states = dn/dɛ.
1+exp()
kBT
(a).
Write down the dispersion relation for free electrons of mass m. What is their group
velocity v?
(b).
Find an expression for g(ɛ) involving the group velocity. Leave your answer in terms
of v.
Chapter 42 Solutions
MASTERINGPHYSICS W/ETEXT ACCESS CODE 6
Ch. 42.1 - If electrons obeyed the exclusion principle but...Ch. 42.2 - Prob. 42.2TYUCh. 42.3 - Prob. 42.3TYUCh. 42.4 - One type of thermometer works by measuring the...Ch. 42.5 - Prob. 42.5TYUCh. 42.6 - Prob. 42.6TYUCh. 42.7 - Suppose a negative charge is placed on the gate of...Ch. 42 - Van der Waals bonds occur in many molecules, but...Ch. 42 - Prob. 42.2DQCh. 42 - The H2+ molecule consists of two hydrogen nuclei...
Ch. 42 - The moment of inertia for an axis through the...Ch. 42 - Prob. 42.5DQCh. 42 - Prob. 42.6DQCh. 42 - Prob. 42.7DQCh. 42 - The air you are breathing contains primarily...Ch. 42 - Prob. 42.9DQCh. 42 - Prob. 42.10DQCh. 42 - What factors determine whether a material is a...Ch. 42 - Prob. 42.12DQCh. 42 - Prob. 42.13DQCh. 42 - Prob. 42.14DQCh. 42 - Prob. 42.15DQCh. 42 - Prob. 42.16DQCh. 42 - Prob. 42.17DQCh. 42 - Prob. 42.18DQCh. 42 - Prob. 42.19DQCh. 42 - Prob. 42.20DQCh. 42 - Prob. 42.21DQCh. 42 - Prob. 42.22DQCh. 42 - Prob. 42.23DQCh. 42 - Prob. 42.24DQCh. 42 - If the energy of the H2 covalent bond is 4.48 eV,...Ch. 42 - An Ionic Bond, (a) Calculate the electric...Ch. 42 - Prob. 42.3ECh. 42 - Prob. 42.4ECh. 42 - Prob. 42.5ECh. 42 - Prob. 42.6ECh. 42 - Prob. 42.7ECh. 42 - Two atoms of cesium (Cs) can form a Cs2 molecule....Ch. 42 - Prob. 42.9ECh. 42 - Prob. 42.10ECh. 42 - A lithium atom has mass 1.17 1026 kg, and a...Ch. 42 - Prob. 42.12ECh. 42 - When a hypothetical diatomic molecule having atoms...Ch. 42 - The vibrational and rotational energies of the CO...Ch. 42 - Prob. 42.15ECh. 42 - Prob. 42.16ECh. 42 - Prob. 42.17ECh. 42 - Prob. 42.18ECh. 42 - Prob. 42.19ECh. 42 - Prob. 42.20ECh. 42 - Prob. 42.21ECh. 42 - Prob. 42.22ECh. 42 - Prob. 42.23ECh. 42 - Prob. 42.24ECh. 42 - Prob. 42.25ECh. 42 - Prob. 42.26ECh. 42 - Prob. 42.27ECh. 42 - Prob. 42.28ECh. 42 - Prob. 42.29ECh. 42 - Prob. 42.30ECh. 42 - Prob. 42.31ECh. 42 - Prob. 42.32ECh. 42 - Prob. 42.33PCh. 42 - Prob. 42.34PCh. 42 - Prob. 42.35PCh. 42 - The binding energy of a potassium chloride...Ch. 42 - (a) For the sodium chloride molecule (NaCl)...Ch. 42 - Prob. 42.38PCh. 42 - Prob. 42.39PCh. 42 - Prob. 42.40PCh. 42 - Prob. 42.41PCh. 42 - Prob. 42.42PCh. 42 - Prob. 42.43PCh. 42 - Prob. 42.44PCh. 42 - Prob. 42.45PCh. 42 - Prob. 42.46PCh. 42 - Prob. 42.47PCh. 42 - Prob. 42.48PCh. 42 - Prob. 42.49PCh. 42 - Prob. 42.50PCh. 42 - Prob. 42.51PCh. 42 - Prob. 42.52PCh. 42 - Prob. 42.53CPCh. 42 - Prob. 42.54CPCh. 42 - Prob. 42.55CPCh. 42 - Prob. 42.56PPCh. 42 - Prob. 42.57PPCh. 42 - Prob. 42.58PP
Knowledge Booster
Similar questions
- H.w// The energy rate is given at T> 0K with the following: 1 {e) N e f(e)g(e)de And compensate for Fermi and density function e3/2 de V (e) = 2m 3/2 h2 e(e-EF)/kT +1 Solve the integration and extend output to be output in the following image: [3 (e) = €f(0) n2 (T 4arrow_forwardGggarrow_forwardPlot the Fermi-Dirac function f(E) versus the energy ratio E/EF at room temperature T=300oK.(Assume EF independent of temperature.)If EF=5ev, determine the energy values at which f (E)=0.5.0.7.0.9 and 0.95?arrow_forward
- The fermi distributions is: F (E, T) = F(E EF,0) =_________ 1 1/2 0 F(E=EF,T) =_ 3/4 What is the probability for state E< Ep at T = 0 K is unoccupied? [Select] , where T can be any temperature.arrow_forwardVolume 2. a) The intrinsic carrier concentration in GaAs at 300 K is 1.8 x 106 cm³. What is the carrier concentration in fm³ at this temperature? b) The mobility of holes in GaAs at 300 K is 400 cm²/V-s. What is the mobility in m²/V-s?arrow_forward6) a) Write down a relation giving the number of electrons occupying the energy states between the energy interval de at ɛ. b) What is the probability that a state 0.1 eV above the Fermi level is occupied by an electron at room temperature ? What is the same probability if that state is 1 eV above the Fermi level ? c) What is a magnetic moment ? The neutron is a neutral particle, but it has a magnetic moment. Explain why it is so.arrow_forward
- 48 Show that P(E), the occupancy probability in Eq. 41-6, is sym- metrical about the value of the Fermi energy; that is, show that P(EF + AE) + P(EF - AE) = 1.arrow_forwardSuppose we have an ideal fermion gas of identical particles in a "box" at T = 0 K. Which of the following statements are true? a. The multiplicity of the gas is =1 b. The multiplicity of the gas is =N! C. If the gas consists of electrons with densities that correspond to the typical densities of conduction electrons in metals, only a part of the electrons can contribute to the heat capacity of the system as the temperature rises. d. If the gas consists of electrons with densities corresponding the typical densities of conduction electrons in metals, all electrons can easily contribute to the heat capacity of the system as the temperature rises.arrow_forwardAsaplikearrow_forward
- The probability of an electron occupying a state 3kT above the Fermi energy in a particular semiconducting sample is 4.74 x 10-2. What is the probability of a hole occupying a state 3kT below the Fermi energy in the same sample?arrow_forwardThe Fermi energy level for a particular material at T = 300 K is 5.50 eV. The electrons in this material follow the Fermi-Dirac distribution function. a) Find the probability of an energy level at 5.50 eV being occupied by an electron. b) Repeat part (a) if the temperature is increased to T = 600 K. (Assume that EF is a constant.). c) Calculate the energy level where probability of finding an electron at room temperature is 70%. d) Calculate the temperature at which there is a 7 percent probability that a state 0.4 eV below the Fermi level will be empty of an electron.arrow_forwardxx=41 Q1. Consider an extrinsic Silicon doped with Indium atoms at a concentration of N₁ = 4×10¹6 cm³ The ionization energy for Indium is given as 0.16eV. Calculate: a) The carrier concentrations no. Po and the Fermi level E-E, at the temperature of T = xx+60 °K. 40+ xx 100 b) The temperature at which Po N₁ cm, for xx<50 60+xx N₁ cm³, for xx 250 100 (Ex: xx = 00 → Po=0.4N₁ -1.6x10¹ cm³; xx=99 Po=1.59N, -6.36x10¹ cmarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning