Explanation The following figure shows the heat exchanger for applying steady flow energy equation. Figure-(1) Write the expression for mass rate balance for the streams. m ˙ 1 + m ˙ 2 = m ˙ 3 Here, the mass flow rate at inlet of section (1) is m ˙ 1 , mass flow rate at the inlet of section (2) is m ˙ 2 , mass flow rate at the exit of section (3) is m ˙ 3 . Write the expression for steady flow energy equation for energy balance. m 1 h 1 + m 2 h 2 − m 3 h 3 = 0 (I) Here, enthalpy at entry for steam is h 1 , enthalpy at exit for steam is h 2 , enthalpy at entry for cooling water is h 3 , enthalpy at exit for cooling water is h 4 , mass flow rate for steam is m ˙ 1 and mass flow rate for cooling water is m ˙ 3 . Substitute m ˙ 1 + m ˙ 2 for m ˙ 3 in Equation (I). m 1 h 1 + m 2 h 2 − ( m ˙ 1 + m ˙ 2 ) h 3 = 0 m 1 h 1 + m 2 h 2 − m ˙ 1 h 3 − m ˙ 2 h 3 = 0 − m 1 ( h 3 − h 1 ) + m 2 ( h 2 − h 3 ) = 0 m 2 = m 1 ( h 3 − h 1 ) ( h 2 − h 3 ) (II) Conclusion: Refer to table A-3 , “Properties of Saturated Water” to obtain 762

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Author: MORAN

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Chapter 4.12, Problem 83P

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The mass flow rate of the steam.

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Chapter 4.12, Problem 80P

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