Explanation Write the expression for mass rate balance for the streams m ˙ 1 = m ˙ 2 − m ˙ 3 m ˙ 3 = m ˙ 1 − m ˙ 2 (I) Here, the mass flow rate at inlet of section (1) is m ˙ 1 , mass flow rate at the exit of section (2) is m ˙ 2 , mass flow rate at the exit of section (3) is m ˙ 3 . Write the expression for steady flow energy equation for energy balance. − Q ˙ C V − m ˙ 1 h 1 + m ˙ 2 h 2 + m ˙ 3 h 3 = 0 Q ˙ C V = m ˙ 2 h 2 + m ˙ 3 h 3 − m ˙ 1 h 1 (VI) Here, heat added to the steam separator is Q ˙ C V , enthalpy at entry for stream at section (1) is h 1 , enthalpy at entry for stram at section (2) is h 2 , enthalpy at exit for stream at section (3)is h 3 , mass flow rate for air at section (1) is m ˙ 1 , mass flow rate for air at section (2) is m ˙ 2 , and mass flow rate for air at section (3) is m ˙ 3 . Write the expression for enthalpy at section (1). h 1 = h f 1 + x 1 h f g 1 (VIII) Here, liquid enthalpy at state (1) is h f 1 , enthalpy of liquid vapor mixture at section (1) is h f g 1 , and dryness fraction at state (1) is x 1 . Conclusion: Substitute 10 kg / s for m ˙ 1 , 6.9 kg / s for m ˙ 2 in Equation (V). m ˙ 3 = 10 kg / s − 6.9 kg / s = 3.1 kg / s Refer to table A-3 “Properties of Saturated Water” to obtain the values of enthalpy 467.11 kJ / kg for h f 1 and 2226.5 kJ / kg for h f g 1 at pressure 1.5 bar . Substitute 0.7 for x 1 , 467

8th Edition

ISBN: 2818440116926

Author: MORAN

Publisher: WILEY CONS

See similar textbooks

Videos

Question

Chapter 4.12, Problem 88P

To determine

The heat transfer from the steam separator.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 4.12, Problem 87P

Chapter 4.12, Problem 89P

Students have asked these similar questions

No use chatgpt

Problem 6 (Optional, extra 6 points) 150 mm 150 mm 120 mm 80 mm 60 mm PROBLEM 18.103 A 2.5 kg homogeneous disk of radius 80 mm rotates with an angular velocity ₁ with respect to arm ABC, which is welded to a shaft DCE rotating as shown at the constant rate w212 rad/s. Friction in the bearing at A causes ₁ to decrease at the rate of 15 rad/s². Determine the dynamic reactions at D and E at a time when ₁ has decreased to 50 rad/s. Answer: 5=-22.01 +26.8} N E=-21.2-5.20Ĵ N

Problem 1. Two uniform rods AB and CE, each of weight 3 lb and length 2 ft, are welded to each other at their midpoints. Knowing that this assembly has an angular velocity of constant magnitude c = 12 rad/s, determine: (1). the magnitude and direction of the angular momentum HD of the assembly about D. (2). the dynamic reactions (ignore mg) at the bearings at A and B. 9 in. 3 in. 03 9 in. 3 in. Answers: HD = 0.162 i +0.184 j slug-ft²/s HG = 2.21 k Ay =-1.1 lb; Az = 0; By = 1.1 lb; B₂ = 0.

Chapter 4 Solutions

FUNDAMENTALS OF ENGINEERING THERMODYNAM

Ch. 4.12 - Prob. 1E Ch. 4.12 - 2. When a drip coffeemaker on-off switch is turned...Ch. 4.12 - Prob. 3E Ch. 4.12 - Prob. 4E Ch. 4.12 - Prob. 5E Ch. 4.12 - Prob. 6E Ch. 4.12 - Prob. 7E Ch. 4.12 - Prob. 8E Ch. 4.12 - Prob. 9E Ch. 4.12 - 10. How does the operator of a pumper-tanker fire...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.