Explanation The following figure shows the heat exchanger for applying steady flow energy equation. Figure-(1) Write the expression for steady flow energy equation for energy balance. Q ˙ C V + m 1 ( h 1 − h 2 ) + m 3 ( h 3 − h 4 ) = 0 m ˙ 1 ( h 1 − h 2 ) = m ˙ 3 ( h 4 − h 3 ) − Q ˙ C V m ˙ 1 = m ˙ 3 ( h 4 − h 3 ) − Q ˙ C V ( h 1 − h 2 ) (I) Here, enthalpy at entry for steam is h 1 , enthalpy at exit for steam is h 2 , enthalpy at entry for cooling water is h 3 , enthalpy at exit for cooling water is h 4 , mass flow rate for steam is m ˙ 1 and mass flow rate for cooling water is m ˙ 3 . Write the expression for heat transfer from the heat exchanger to its surrounding. h 1 − h 2 = x 1 h f g (II) Here, dryness fraction at section (1) is x 1 . Write the expression for heat transfer from the heat exchanger to its surrounding. Q ˙ C V = − 0.10 [ m ˙ 3 ( h 4 − h 3 ) ] (III) Here, heat transfer from the heat exchanger is Q ˙ C V . Write the expression for enthalpy difference between state (3) and state (4). h 4 − h 3 = c v ( T 4 − T 3 ) + v ( P 4 − P 3 ) (IV) Here, temperature at state (3) is T 3 , temperature at state (4) is T 4 , pressure at state (3) is P 3 , pressure at state (4) is P 4 , volume at state (3) and (4) is same v , and specific heat at constant volume is c v Conclusion: Refer to table A-3 ,“Properties of saturated water” to obtain the values of specific enthalpy of liquid and vapour mixture at 250 kPa as 2181.5 kJ / kg . Substitute 2181.5 kJ / kg for h f g at pressure 250 kPa and 0

8th Edition

ISBN: 2818440116926

Author: MORAN

Publisher: WILEY CONS

See similar textbooks

Concept explainers

Heat Exchangers

Heat exchangers are the types of equipment that are primarily employed to transfer the thermal energy from one fluid to another, provided that one of the fluids should be at a higher thermal energy content than the other fluid.

Heat Exchanger

The heat exchanger is a combination of two words ''Heat'' and ''Exchanger''. It is a mechanical device that is used to exchange heat energy between two fluids.

Videos

Question

Chapter 4.12, Problem 76P

To determine

The mass flow rate of steam.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 4.12, Problem 75P

Chapter 4.12, Problem 77P

Students have asked these similar questions

HW12 A multiple-disc clutch has five plates having four pairs of active friction surfaces. If the intensity of pressure is not to exceed 0.127 N/mm², find the power transmitted at 500 r.p.m. The outer and inner radii of friction surfaces are 125 mm and 75 mm respectively. Assume uniform wear and take the coefficient of friction = 0.3.

The sketch below gives some details of the human heart at rest. What is the total power requirement (work/time) for an artificial heart pump if we use a safety factor of 5 to allow for inefficiencies, the need to operate the heart under stress, etc.? Assume blood has the properties of water. p pressure above atmosphere blood going to the lungs for a fresh charge of oxygen p = 2.9 kPa 25v pulmonary artery d = 25mm fresh oxygenated blood from the lungs p = 1.0 kPa vena cava d=30mm right auricle pulmonary vein, d = 28mm aorta, d=20mm spent blood returning from left auricle the body p = 0.66 kPa right left ventricle ventricle blood to feed the body, p 13 kPa normal blood flow = 90 ml/s

4- A horizontal Venturi meter is used to measure the flow rate of water through the piping system of 20 cm I.D, where the diameter of throat in the meter is d₂ = 10 cm. The pressure at inlet is 17.658 N/cm2 gauge and the vacuum pressure of 35 cm Hg at throat. Find the discharge of water. Take Cd = 0.98.

Chapter 4 Solutions

FUNDAMENTALS OF ENGINEERING THERMODYNAM

Ch. 4.12 - Prob. 1E Ch. 4.12 - 2. When a drip coffeemaker on-off switch is turned...Ch. 4.12 - Prob. 3E Ch. 4.12 - Prob. 4E Ch. 4.12 - Prob. 5E Ch. 4.12 - Prob. 6E Ch. 4.12 - Prob. 7E Ch. 4.12 - Prob. 8E Ch. 4.12 - Prob. 9E Ch. 4.12 - 10. How does the operator of a pumper-tanker fire...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.