Explanation Write the energy rate balance equation. 0 = Q ˙ cv − W ˙ cv + m ˙ [ ( h 1 − h 2 ) + ( V 1 2 − V 2 2 ) 2 + g ( z 1 − z 2 ) ] (I) Here, the rate of heat transfer is Q ˙ cv , rate of work transfer is W ˙ cv , rate of mass flow is m ˙ , the enthalpy is h , velocity is V , gravitational acceleration is g , the elevation is z and the suffixes cv, 1 and 2 indicates control volume, initial and final state of the system respectively. Write the formula for change in enthalpy in terms of liquid condition. h 1 − h 2 = [ h f ( T 1 ) + v f ( T 1 ) [ p 1 − p sat ( T 1 ) ] ] − [ h f ( T 2 ) + v f ( T 2 ) [ p 2 − p sat ( T 2 ) ] ] (II) Here, the enthalpy of liquid corresponding to the temperature of T 1 is h f ( T 1 ) , the specific volume corresponding to the temperature of T 1 is v f ( T 1 ) , the pressure is p and the saturation pressure is p sat ; the suffixes 1 and 2 indicates the inlet and exit states of the liquid. It is given that there is no significant changes in the temperature, pressure and kinetic energy of the water. Hence, neglect the kinetic energy effect i.e. ( V 1 2 − V 2 2 ) 2 = 0 . When, there is no significant changes in the temperature, pressure of the water, the change in enthalpy becomes negligible. h 1 − h 2 = [ h f ( T 1 ) + v f ( T 1 ) [ p 1 − p sat ( T 1 ) ] ] − [ h f ( T 2 ) + v f ( T 2 ) [ p 2 − p sat ( T 2 ) ] ] = 0 Then the Equation (I) becomes as follows to obtain the heat transfer rate ( Q ˙ cv )

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Chapter 4.12, Problem 65P

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The rate of heat transfer between the pump and its surroundings, in hp and Btu/min.

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Chapter 4.12, Problem 64P

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The rate of heat transfer between the pump and its surroundings, in hp and Btu/min .

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The rate of heat transfer between the pump and its surroundings, in hp and Btu/min.

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