(a) Explanation Given information: The load ( P ) acting on the split ring is 2 , 500 N . The inner diameter ( d 1 ) and outer diameter ( d 2 ) of the split ring are 40 mm and 90 mm . Calculation: Calculate the inner radius ( r 1 ) and outer radius ( r 2 ) of the split ring as follows: r 1 = 1 2 d 1 = 1 2 × 40 = 20 mm r 2 = 1 2 d 2 = 1 2 × 90 = 45 mm Calculate the height ( h ) of the cross-section using the relation: h = r 2 − r 1 Substitute 20 mm for r 1 and 45 mm for r 2 . h = 45 − 20 = 25 mm Calculate the area of the cross-section as follows: Substitute 14 mm for b and 25 mm for h . A = b h = 14 × 25 = 350 mm 2 Calculate the mean radius of the cross-section as follows: Substitute 20 mm for r 1 and 45 mm for r 2 . r ¯ = 1 2 ( r 1 + r 2 ) = 1 2 × ( 20 + 45 ) = 32.5 mm Show the formula for the radius ( R ) of the neutral surface for the cross-section as follows: R = h ln ( r 2 r 1 ) (1) Substitute 20 mm for r 1 , 45 mm for r 2 , and 25 mm for h in Equation (2). R = 25 ln ( 45 20 ) = 25 ln ( 2.25 ) = 25 0.810930 = 30 (b) To determine Find the stress at point B .

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Chapter 4.10, Problem 170P

(a)

To determine

Find the stress at point A.

(b)

To determine

Find the stress at point B.

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Chapter 4.10, Problem 169P

Chapter 4.10, Problem 171P

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Find the stress at point A .

Solution Summary: The author explains how to find the stress at point A. The load (P) acting on the split ring is 2,500N.

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