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Concept explainers
Interpretation: From the given properties, the properties possessed by the given element in position 117 should be determined.
Concept Introduction:
Periodic Table: The available chemical elements are arranged considering their
In periodic table the horizontal rows are called periods and the vertical column are called group. There are seven periods and 18 groups present in the table and some of those groups are given special name as follows,
Atomic Number: Atomic number of the element is equal to the number of protons present in the nucleus of the element which is denoted by symbol Z. The superscript presents on the left side of the
Electronic configuration: It is used to denote the distribution of electrons placed over orbitals that present in the atom.
The rules followed by the electrons are as follows,
The electrons gets distributed starting from lower energy orbital to higher energy orbital, pairing of electrons starts after all the orbitals are singly filled and finally, no two electrons that have same spin can occupy the same orbital.
In periodic table the horizontal rows are called periods and the vertical column are called group.
Cation: Removal of electron from the atom results to form positively charged ion called cation.
Anion: Addition of electron to atom results to form negatively charged ion called anion.
The net charge present in the element denotes the presence or absence of electrons in the element.
Metalloid (semi-metal): The chemical element is considered as metalloid if it contains properties of both metals and the non-metals.
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Chapter 4 Solutions
Chemistry: Atoms First
- Classify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forwardNonearrow_forwardQ4: Comparing (3S,4S)-3,4-dimethylhexane and (3R,4S)-3,4-dimethylhexane, which one is optically active? Briefly explain.arrow_forward
- Nonearrow_forwardNonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forward
- Determine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward3) Catalytic hydrogenation of the compound below produced the expected product. However, a byproduct with molecular formula C10H12O is also formed in small quantities. What is the by product?arrow_forwardWhat is the ΔHorxn of the reaction? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) ΔHorxn 1= ________ kJ/molarrow_forward
- = +92kJ ΔΗ = +170kJ Use the following reactions: 2NH3(9) N2(g) + 3H2(g) → 11/N2(g) + 2H2O (1) → NO2(g) + 2H2(g) Determine the DH° of this reaction: NO2(g) + H2(g) → 2(g) → 2H2O(l) + NH3(9) ΔΗarrow_forwardDetermine the entropy change for the reaction SO2(g) + O2(g) following information: Standard Entropy Values of Various Substance Substance SO2(g) 02(g) SO3(g) So (J/mol K) 248.2 205.0 256.8 → SO3(g) given thearrow_forwardIndicate which one of the following reactions most certainly results in a negative AS sys. O1402(g) + 3NH4NO3 (s) + C10 H22(1) → 3N2(g) + 17H2O(g) + 10CO2(g) ○ CO2(aq) = CO2(g) ○ H₂O(g) = H₂O(s) CaCO3(g) = CaO(s) + CO2(g) O CuSO4.5H2O(s) = CuSO4(s) + 5H2O(g)arrow_forward
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