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Concept explainers
Interpretation: The elements that possess properties similar to the given element, chlorine should be determined.
Concept Introduction:
Periodic Table: The available chemical elements are arranged considering their
In periodic table the horizontal rows are called periods and the vertical column are called group. There are seven periods and 18 groups present in the table and some of those groups are given special name as follows,
Atomic Number: Atomic number of the element is equal to the number of protons present in the nucleus of the element which is denoted by symbol Z. The superscript presents on the left side of the
Electronic configuration: It is used to denote the distribution of electrons placed over orbitals that present in the atom.
The rules followed by the electrons are as follows,
The electrons gets distributed starting from lower energy orbital to higher energy orbital, pairing of electrons starts after all the orbitals are singly filled and finally, no two electrons that have same spin can occupy the same orbital.
In periodic table the horizontal rows are called periods and the vertical column are called group.
Cation: Removal of electron from the atom results to form positively charged ion called cation.
Anion: Addition of electron to atom results to form negatively charged ion called anion.
The net charge present in the element denotes the presence or absence of electrons in the element.
Metalloid (semi-metal): The chemical element is considered as metalloid if it contains properties of both metals and the non-metals.
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Chapter 4 Solutions
Chemistry: Atoms First
- Comparing two means. Horvat and co-workers used atomic absorption spectroscopy to determine the concentration of Hg in coal fly ash. Of particular interest to the authors was developing an appropriate procedure for digesting samples and releasing the Hg for analysis. As part of their study they tested several reagents for digesting samples. Their results using HNO3 and using a 1+3 mixture of HNO3 and HCl are shown here. All concentrations are given as ppb Hg sample. HNO3: 161, 165, 160, 167, 166 1+3 HNO3–HCl: 159, 145, 140, 147, 143, 156 Determine whether there is a significant difference between these methods at the 95% confidence interval.arrow_forwardComparison of experimental data to “known” value. Monna and co-workers used radioactive isotopes to date sediments from lakes and estuaries.21 To verify this method they analyzed a 208Po standard known to have an activity of 77.5 decays/min, obtaining the following results. 77.09, 75.37, 72.42, 76.84, 77.84, 76.69, 78.03, 74.96, 77.54, 76.09, 81.12, 75.75 Do the results differ from the expected results at the 95% confidence interval?arrow_forwardExplain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement? if the standard deviation is 0.01 and the propagated uncertainty is 0.03arrow_forward
- Propagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 7.65±0.04 + 5.28±0.02 – 1.12±0.01 85.6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forwardExplain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement?arrow_forwardCircle the compound in each pair where the indicated bond vibrates at higher frequency. WHY IS THIS? Provide thorough explanation to tie topic.arrow_forward
- How can you distinguish between each pair of compounds below using IR? Cite a bond and frequency that can be used to distinguish. Provide thorough steps and explanation.arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 65±0.04 + 5.28±0.02 – 1.12±0.01 6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forwardMatch to correct spectrum and explain the bonds and frequencies used to tell what spectrum connected to the given option. Thanks.arrow_forward
- Draw the virtual orbitals for the planar and pyramidal forms of CH3 and for the linear and bent forms of CH2arrow_forwardQ2: Draw the molecules based on the provided nomenclatures below: (2R,3S)-2-chloro-3-methylpentane: (2S, 2R)-2-hydroxyl-3,6-dimethylheptane:arrow_forwardQ3: Describes the relationship (identical, constitutional isomers, enantiomers or diastereomers) of each pair of compounds below. ག H CH3 OH OH CH3 H3C OH OH OH ////////// C CH3 CH3 CH3 CH3 H3C CH 3 C/III..... Physics & Astronomy www.physics.northweste COOH H нош..... H 2 OH HO CH3 HOOC H CH3 CH3 CH3 Br. H H Br and H H H Harrow_forward
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