UNIVERSITY PHYSICS UCI PKG
11th Edition
ISBN: 9781323575208
Author: YOUNG
Publisher: PEARSON C
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Chapter 41, Problem 41.17DQ
To determine
Why there is a difference in the ionization energy of the alkali metals that are about
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The ionization energies of the alkali metals (that is, the lowest energy required to remove one outer electron when the atom is in its ground state) are about 4 or 5 eV, while those of the noble gases are in the range from 11 to 25 eV. Why is there a difference?
The electron in a hydrogen atom is in an exited state for which n = 3. What is the highest frequency that can be radiated?
(Given: E1 =-13.6 eV, E2 = -3.40 eV , E3 = -1.51 eV)
The first five energy levels of the hydrogen atom are at n = 1, − 13.6 eV; n = 2, − 3.4 eV;n = 3, − 1.51 eV; n = 4, − 0.85 eV; n = 5, − 0.54 eV. A hydrogen discharge lamp givesan infrared spectrum that includes a sharp line at a wavelength of 4 µm, coming from electronsexcited by the discharge to a higher level, and then jump down to a lower level. Determine theenergy lost by these electrons, and identify the higher and lower levels involved.
Chapter 41 Solutions
UNIVERSITY PHYSICS UCI PKG
Ch. 41.1 - Prob. 41.1TYUCh. 41.2 - Prob. 41.2TYUCh. 41.3 - Prob. 41.3TYUCh. 41.4 - In this section we assumed that the magnetic field...Ch. 41.5 - In which of the following situations is the...Ch. 41.6 - Prob. 41.6TYUCh. 41.7 - Prob. 41.7TYUCh. 41.8 - Prob. 41.8TYUCh. 41 - Prob. 41.1DQCh. 41 - Prob. 41.2DQ
Ch. 41 - Prob. 41.3DQCh. 41 - Prob. 41.4DQCh. 41 - Prob. 41.5DQCh. 41 - Prob. 41.6DQCh. 41 - Prob. 41.7DQCh. 41 - In the ground state of the helium atom one...Ch. 41 - Prob. 41.9DQCh. 41 - Prob. 41.10DQCh. 41 - Prob. 41.11DQCh. 41 - Prob. 41.12DQCh. 41 - Prob. 41.13DQCh. 41 - Prob. 41.14DQCh. 41 - Prob. 41.15DQCh. 41 - Prob. 41.16DQCh. 41 - Prob. 41.17DQCh. 41 - Prob. 41.18DQCh. 41 - Prob. 41.19DQCh. 41 - Prob. 41.20DQCh. 41 - Prob. 41.21DQCh. 41 - Prob. 41.22DQCh. 41 - Prob. 41.23DQCh. 41 - Prob. 41.1ECh. 41 - Prob. 41.2ECh. 41 - Prob. 41.3ECh. 41 - Prob. 41.4ECh. 41 - Prob. 41.5ECh. 41 - Prob. 41.6ECh. 41 - Prob. 41.7ECh. 41 - Prob. 41.8ECh. 41 - Prob. 41.9ECh. 41 - Prob. 41.10ECh. 41 - Prob. 41.11ECh. 41 - Prob. 41.12ECh. 41 - Prob. 41.13ECh. 41 - Prob. 41.14ECh. 41 - Prob. 41.15ECh. 41 - Prob. 41.16ECh. 41 - Prob. 41.17ECh. 41 - Prob. 41.18ECh. 41 - A hydrogen atom in a 3p state is placed in a...Ch. 41 - Prob. 41.20ECh. 41 - Prob. 41.21ECh. 41 - Prob. 41.22ECh. 41 - Prob. 41.23ECh. 41 - Prob. 41.24ECh. 41 - Prob. 41.25ECh. 41 - Prob. 41.26ECh. 41 - Prob. 41.27ECh. 41 - Prob. 41.28ECh. 41 - Prob. 41.29ECh. 41 - (a) Write out the ground-state electron...Ch. 41 - Prob. 41.31ECh. 41 - Prob. 41.32ECh. 41 - Prob. 41.33ECh. 41 - Prob. 41.34ECh. 41 - Prob. 41.35ECh. 41 - Prob. 41.36ECh. 41 - Prob. 41.37ECh. 41 - Prob. 41.38ECh. 41 - Prob. 41.39PCh. 41 - Prob. 41.40PCh. 41 - Prob. 41.41PCh. 41 - Prob. 41.42PCh. 41 - Prob. 41.43PCh. 41 - Prob. 41.44PCh. 41 - Prob. 41.45PCh. 41 - Prob. 41.46PCh. 41 - Prob. 41.47PCh. 41 - Prob. 41.48PCh. 41 - Prob. 41.49PCh. 41 - Prob. 41.50PCh. 41 - Prob. 41.51PCh. 41 - Prob. 41.52PCh. 41 - Prob. 41.53PCh. 41 - Prob. 41.54PCh. 41 - Prob. 41.55PCh. 41 - Prob. 41.56PCh. 41 - Prob. 41.57PCh. 41 - Effective Magnetic Field. An electron in a...Ch. 41 - Prob. 41.59PCh. 41 - Prob. 41.60PCh. 41 - Prob. 41.61PCh. 41 - Prob. 41.62PCh. 41 - Prob. 41.63PCh. 41 - Prob. 41.64PCh. 41 - Prob. 41.65PCh. 41 - Prob. 41.66PCh. 41 - Prob. 41.67PCh. 41 - Prob. 41.68CPCh. 41 - Prob. 41.69CPCh. 41 - Prob. 41.70PPCh. 41 - Prob. 41.71PPCh. 41 - Prob. 41.72PPCh. 41 - Prob. 41.73PP
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- What are the possible values of m for an electron in the n = 4 state?arrow_forwardFor an electron in a hydrogen atom in the n=2 state, compute: (a) the angular momentum; (b) the kinetic energy; (c) the potential energy; and (d) the total energy.arrow_forwardThe allowed energies of a simple atom are 0.0 eV, 4.0 eV, and 6.0 eV. An electron traveling at a speed of 1.6 * 106 m/s collisionally excites the atom. What are the minimum and maximum speeds the electron could have after the collision?arrow_forward
- The Bohr model correctly predicts the main energy levels not only for atomic hydrogen but also for other "one-electron" atoms where all but one of the atomic electrons has been removed, such as in He+ (one electron removed) or Li++ (two electrons removed). (a) Predict the energy in eV of a photon emitted in a transition from the first excited state to the ground state in eV for a system consisting of a nucleus containing Z = 21 protons and just one electron.arrow_forwardAn electron with a speed of 5.00 × 106 m/s collides with an atom. The collision excites the atom from its ground state (0 eV) to a state with an energy of 3.80 eV. What is the speed of the electron after the collision?arrow_forwardUsing the information from the hydrogen atom diagram provided, what energy level would the electron in the hydrogen atom jump to if it is initially in the n = 2 energy level and collides with a free electron that has a kinetic energy of 2 eV?arrow_forward
- Light of wavelength 102.6 nm is emitted by a hydrogen atom. What are the (a) higher quantum number and (b) lower quantum number of the transition producing this emission? (c) What is the name of the series that includes the transition?arrow_forward(a) The Lyman series in hydrogen is the transition from energy levels n = 2, 3, 4, ... to the ground state n = 1. The energy levels are given by 13.60 eV En n- (i) What is the second longest wavelength in nm of the Lyman series? (ii) What is the series limit of the Lyman series? [1 eV = 1.602 x 1019 J, h = 6.626 × 10-34 J.s, c = 3 × 10° m.s] %3D Two emission lines have wavelengts A and + A2, respectively, where AA <<2. Show that the angular separation A0 in a grating spectrometer is given aproximately by (b) A0 = V(d/m)-2 where d is the grating constant and m is the order at which the lines are observed.arrow_forwardA hydrogen atom has its electron in the n-3 state. How much energy would have to be absorbed by the atom for it to become ionized from this level? What is the frequency of the photon that could produce this result? An atom has 46 electrons. What is the smallest value of n needed so that all 46 electrons occupy the lowest possible quantum states consistent with the Pauli exclusion principle? O 1.51 eV 3.65 x 10^14 Hz, n = 5 O 1.51 eV 3.93 x 10^14 Hz. n=5 O 1.58 eV 3.93 x 10^14 Hz, n=5 1.51 eV 3.65 x 10^14 Hz. n-4 O 144 eV 3.65 x 10^14 Hz, n=6arrow_forward
- The energy difference between the 1st excited state (n = 2) and the 2nd excited state (n = 3) in the hydrogen atom is 1.9 eV, what is the wavelength of the emission line resulting from the electron transitions between those two levels? Give your answer in units of nanometers (nm).arrow_forwardA photon is absorbed by a hydrogen atom in the ground state. n=3 n=2 n=1 n=7 n=6 n=s n=4 n n 11=3 n=2 n=1 + E = 0 Es=-0.544 eV E4-0.850 eV E3 = -1.51 eV E2 = -3.40 eV E1-13.6 eV Ground state If the electron is boosted from to the n = 2, what was the energy of the photon? Give your answer in electron volts (eV). evarrow_forwardAn electron is in a hydrogen atom with n = 2 and ℓ = 1. (a) Find all the possible angles between the orbital angular momentum vector and the z-axis. (b) Suppose the atom absorbs a photon and rises from the n = 2 and ℓ = 1 state to the n = 3 state. Using conversation of angular momentum, what are the possible values of the final value of ℓ in the n = 3 state?arrow_forward
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