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A person stands on a scale, which then reads 600 N. (a) What force is exerted on the scale by the person? (b) What force is exerted on the person by the scale? (c) What would happen to the reading as the person began to jump straight up?
(a)
![Check Mark](/static/check-mark.png)
The magnitude of the force applied on the scale by the person if he stands on a scaleand the readingis
Answer to Problem 9SP
Solution:
Explanation of Solution
Given data:
The weight of the person is
The scale is at rest, so there will be no acceleration.
Formula used:
Write the expression for the first condition of force equilibrium:
Here,
Explanation:
Draw the free body diagram of the scale when the person stands on it:
In the diagram,
Recall the expression for the first condition of force equilibrium:
Consider that the direction of the upward forces is positive and the direction of the downward forces is negative. Therefore,
Substitute
From Newton’s third law, the force exerted on the scale by a person is equal and opposite to the weight of the person and it acts in the downward direction because the force applied by the person is in the downward direction. So, the magnitude of force applied by the person to the scale should be equal to the normal reaction force applied by the contact surface of the scale to the person.
Conclusion:
The magnitude of the force applied on the scale by the person is
(b)
![Check Mark](/static/check-mark.png)
The magnitude of the force applied on the person by the scale if he stands on a scale and the scale reads
Answer to Problem 9SP
Solution:
Explanation of Solution
Given data:
The weight of the person is
The scale is at rest, so there will be no acceleration.
Formula used:
Write the expression for the first condition of force equilibrium:
Here,
Explanation:
Draw the free body diagram of the scale:
In the above diagram,
Recall the expression for the first condition of force equilibrium:
Consider that the direction of the upward forces is positive and the direction of the downward forces is negative. Therefore,
Substitute
From Newton’sthird law, the force exerted on the person by the scale is equal and opposite to the weight of the person and it actsin the upward direction because the force exerted by the scale is in the upward direction.
Conclusion:
Therefore, the magnitude of the force applied on the person by the scale is
(c)
![Check Mark](/static/check-mark.png)
The reading on a scale when the person begins to jump straight up on a scale.
Answer to Problem 9SP
Solution:
Increase
Explanation of Solution
Given data:
The weight of the person is
The scale is at rest, so there will be no acceleration.
Formula used:
Write the expression for Newton’s second law of motion:
Here,
Explanation:
Draw the free body diagram of the person when he begins to jump:
In the diagram given above,
Recall the expression for Newton’s second law of motion along the vertical direction:
Consider that the direction of the upward forces is positive and the direction of the downward forces is negative. Therefore,
Here,
Conclusion:
Therefore, as the person starts to jump straight up, the reading of the scale would increase.
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Chapter 4 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
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