The increase in bond strength by the removal of an electron in case of O 2 and the decrease in bond strength by the removal of an electron from N 2 is to be explained. Concept introduction: The electronic configuration for multi-electron diatomic is written using the molecular orbitals, derived from the H 2 + molecular ion. The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as, Bond order = [ ( Electrons in bonding orbitals ) − ( Electrons in anti-bonding orbitals ) ] 2 As the bond order increases, the stability also increases. The bond order is directly proportional to the bond energy and inversely proportional to the bond length. To determine: The reason behind the increase in bond strength in case of O 2 and the decrease in the same in case of N 2 on the removal of an electron.
The increase in bond strength by the removal of an electron in case of O 2 and the decrease in bond strength by the removal of an electron from N 2 is to be explained. Concept introduction: The electronic configuration for multi-electron diatomic is written using the molecular orbitals, derived from the H 2 + molecular ion. The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as, Bond order = [ ( Electrons in bonding orbitals ) − ( Electrons in anti-bonding orbitals ) ] 2 As the bond order increases, the stability also increases. The bond order is directly proportional to the bond energy and inversely proportional to the bond length. To determine: The reason behind the increase in bond strength in case of O 2 and the decrease in the same in case of N 2 on the removal of an electron.
Solution Summary: The author explains that the increase in the bond order on the removal of an electron is the reason behind the stability of the O_ 2 molecule.
Interpretation: The increase in bond strength by the removal of an electron in case of
O2 and the decrease in bond strength by the removal of an electron from
N2 is to be explained.
Concept introduction: The electronic configuration for multi-electron diatomic is written using the molecular orbitals, derived from the
H2+ molecular ion.
The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as,
As the bond order increases, the stability also increases. The bond order is directly proportional to the bond energy and inversely proportional to the bond length.
To determine: The reason behind the increase in bond strength in case of
O2 and the decrease in the same in case of
N2 on the removal of an electron.
JON
Determine the bund energy for
UCI (in kJ/mol Hcl) using me
balanced chemical equation and
bund energies listed?
का
(My (9) +36/2(g)-(((3(g) + 3(g)
A Hryn = -330. KJ
bond energy
и-н 432
bond
bond
C-1413
C=C 839 N-H
391
C=O 1010
S-H 363
б-н 467
02 498
N-N
160
N=N
243
418
C-C 341
C-0 358
C=C
C-C 339 N-Br
243
Br-Br
C-Br 274
193
614
(-1 214||(=olin (02) 799
C=N
615
AAL
Determine the bond energy for HCI (
in kJ/mol HCI) using he balanced
cremiculequecticnand bund energles
listed? also c double bond to N is
615, read numbets carefully please!!!!
Determine the bund energy for
UCI (in kJ/mol cl) using me
balanced chemical equation and
bund energies listed?
51
(My (9) +312(g)-73(g) + 3(g)
=-330. KJ
спод
bond energy
Hryn
H-H
bond
band
432
C-1 413
C=C 839 NH
391
C=O 1010
S-1 343
6-H
02 498
N-N
160
467
N=N
C-C
341
CL-
243
418
339 N-Br
243
C-O
358
Br-Br
C=C
C-Br 274
193
614
(-1 216 (=olin (02) 799
C=N
618
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Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY