The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C − C − O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined. Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number. If the steric number is 4 , the atom is sp 3 hybridized. If the steric number is 3 , the atom is sp 2 hybridized. If the steric number is 2 , the atom is sp hybridized. Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding. To determine: The Lewis structure, the C − C − O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

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Answer 1

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Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

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Answer 2

Question

Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

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Answer 3

Question

Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

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Answer 4

Question

Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

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Answer 5

Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

Answer 6

Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

Answer 7

Chapter 4, Problem 55E

Interpretation Introduction

Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.

Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.

If the steric number is 4 , the atom is sp3 hybridized.

If the steric number is 3 , the atom is sp2 hybridized.

If the steric number is 2 , the atom is sp hybridized.

Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.

To determine: The Lewis structure, the C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 4 - Explain the main postulate of the VSEPR model....Ch. 4 - Explain why CF4 and Xef4 are nonpolar compounds...Ch. 4 - Consider the following compounds: CO2, SO2, KrF2,...Ch. 4 - Prob. 4RQ Ch. 4 - What hybridization is required for central atoms...Ch. 4 - Prob. 6RQ Ch. 4 - Prob. 7RQ Ch. 4 - What are molecular orbitals? How do they compare...Ch. 4 - Explain the difference between the and MOs for...Ch. 4 - Prob. 3ALQ

Solution Summary: The author explains the Lewis structures of two compounds, Biacetyl and Acetoin, and the number of sigma and pi bonds present in both the given compounds.

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