Chapter 4, Problem 66GP

To determine

To find: The magnitude of the force exerted by the heat muscle.

Answer to Problem 66GP

The magnitude of the force exerted is $\left(20\times {10}^{-3}\right)\text{N}$ .

Explanation of Solution

Given Data:

  $\begin{array}{l}\text{mass of blood}\left(m\right)=20\text{g}\\ \text{initial velocity}\left(v_o\right)=0.25\text{m/s}\\ \text{final velcoty}\left(v\right)=0.35\text{m/s}\\ \text{time interval}\left(t\right)=0.1\text{sec}\end{array}$

Calculation:

Here, the average acceleration is given as:

  $\begin{array}{l}a=\frac{v-v_o}{t}\\ =\frac{0.35-0.25}{0.10}{\text{m/s}}^{\text{2}}\\ =1{\text{m/s}}^2\end{array}$

Now, the force exerted by the heart muscle:

  $\begin{array}{l}F=m.a\\ =\left(20\times {10}^{-3}\right)1\\ =\left(20\times {10}^{-3}\right)\text{N}\end{array}$