Chapter 4, Problem 60P

To determine

The coefficient of friction.

Answer to Problem 60P

Solution:

Coefficient of friction= ${\mu }_k$=0.213

Explanation of Solution

Given:

$\theta$

=12^o

Formula used:

${\displaystyle \sum F=ma}$

Calculation:

$\begin{array}{l}\text{when skier moves downhill}\\ mg\sin \theta -{\mu }_{k}mg\cos \theta =ma\\ a=0\\ mg\sin \theta -{\mu }_{k}mg\cos \theta =m(0)\\ mg\sin \theta ={\mu }_{k}mg\cos \theta \\ {\mu }_k=\frac{\sin \theta }{\cos \theta }\\ {\mu }_k=\tan \theta \\ {\mu }_k=\tan {12}^{\circ }\\ {\mu }_k=0.213\end{array}$