Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 4, Problem 2P
To determine

The weight of an astronaut on −

  1. Earth
  2. Moon
  3. On Mars
  4. In outer space traveling with constant velocity

Expert Solution & Answer
Check Mark

Answer to Problem 2P

Solution:

  1. The weight of an astronaut on Earth is 666.4 N
  2. The weight of an astronaut on Moon is 115.6 N
  3. The weight of an astronaut on Mars is 251.6 N
  4. The weight of an astronaut in an outer space is 0 N

Explanation of Solution

The weight of an object is the product of the mass of an object to the acceleration due to the gravity. The expression of weight is given as follows:

  W=mg

Here, m is the mass of an astronaut and g is the acceleration due to gravity.

Given:

Mass of an astronaut m=68 kg

Gravity of Moon g=1.7 m/s2

Gravity of Mars g=3.7 m/s2

Formula used:

  W=mg

Calculation:

Part (a):

Substitute, m=68 kg and g=9.8 m/s2 in equation (1) so the weight of an astronaut on Earth is given as follows:

  W=mg=9.8 m/s2(68 kg)=666.4 N

Part (b):

Substitute, m=68 kg and g=1.7 m/s2 in equation (1) so the weight of an astronaut on the moon is given as follows:

  W=mg=1.7 m/s2(68 kg)=115.6 N

Part (c):

Substitute, m=68 kg and g=3.7 m/s2 in equation (1) so the weight of an astronaut on Mars is given as follows:

  W=mg=3.7 m/s2(68 kg)=251.6 N

Part (d):

The effect of gravity on in outer space is zero so the weight of an astronaut in an outer space is given as follows:

  W=mg=0 m/s2(68 kg)=0 N

Conclusion:

  1. Hence, the weight of an astronaut on Earth is 666.4 N .
  2. Hence, the weight of an astronaut on Moon is 115.6 N .
  3. Hence, the weight of an astronaut on Mars is 251.6 N .
  4. Hence, the weight of an astronaut in an outer space is 0 N .

Chapter 4 Solutions

Physics: Principles with Applications

Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 14QCh. 4 - Prob. 15QCh. 4 - Prob. 16QCh. 4 - Prob. 17QCh. 4 - Prob. 18QCh. 4 - A block is given a brief push so that it slides up...Ch. 4 - Prob. 20QCh. 4 - Prob. 21QCh. 4 - What force is needed to accelerate a sled (mass =...Ch. 4 - Prob. 2PCh. 4 - How much tension must a rope withstand if it is...Ch. 4 - According to a simplified model of a mammalian...Ch. 4 - Superman must stop a 120-km/h train in 150 m to...Ch. 4 - A person has a reasonable chance of surviving an...Ch. 4 - What average force is required to stop a 950-kg...Ch. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - A box weighing 77.0 N rests on a table. A rope...Ch. 4 - Figure 4-46 Problem 21. 21. (I) Draw the free-body...Ch. 4 - Prob. 21PCh. 4 - Arlene is to walk across a “high wire" strung...Ch. 4 - A window washer pulls herself upward using the...Ch. 4 - One 3.2-kg paint bucket is hanging by a massless...Ch. 4 - Prob. 25PCh. 4 - A train locomotive is pulling two cars of the same...Ch. 4 - Prob. 27PCh. 4 - A 27-kg chandelier hangs from a ceiling on a...Ch. 4 - Prob. 29PCh. 4 - Figure 4-53 [shows a block (mass mA) on a smooth...Ch. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - 35. (Ill) Suppose the pulley in Fig. 4-55 is...Ch. 4 - Prob. 34PCh. 4 - A force of 35.0 N is required to start a 6.0-kg...Ch. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - A box is given a push so that it slides across the...Ch. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - 46. (II) For the system of Fig. 4-32 (Example...Ch. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - A person pushes a 14.0-kg lawn mower at constant...Ch. 4 - Prob. 49PCh. 4 - (a) A box sits at rest on a rough 33° inclined...Ch. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - A 25.0-kg box is released on a 27° incline and...Ch. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - The crate shown in Fig. 4-60 lies on a plane...Ch. 4 - A crate is given an initial speed of 3.0 m/s up...Ch. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - The coefficient of kinetic friction for a 22-kg...Ch. 4 - On an icy day, you worry about parking your car in...Ch. 4 - Two masses mA= 2.0 kg and mB= 5.0 kg are on...Ch. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66GPCh. 4 - Prob. 67GPCh. 4 - Prob. 68GPCh. 4 - Prob. 69GPCh. 4 - Prob. 70GPCh. 4 - Prob. 71GPCh. 4 - Prob. 72GPCh. 4 - Prob. 73GPCh. 4 - Prob. 74GPCh. 4 - Prob. 75GPCh. 4 - Prob. 76GPCh. 4 - Prob. 77GPCh. 4 - Prob. 78GPCh. 4 - Prob. 79GPCh. 4 - Prob. 80GPCh. 4 - Prob. 81GPCh. 4 - Prob. 82GPCh. 4 - Prob. 83GPCh. 4 - Prob. 84GPCh. 4 - Prob. 85GPCh. 4 - Prob. 86GPCh. 4 - Prob. 87GPCh. 4 - Prob. 88GPCh. 4 - Prob. 89GP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
Newton's First Law of Motion: Mass and Inertia; Author: Professor Dave explains;https://www.youtube.com/watch?v=1XSyyjcEHo0;License: Standard YouTube License, CC-BY