The force exerted by the wind on a sailboat is approximately perpendicular 10 the sail and proportional to the component of the wind velocity perpendicular to the sail. For the 800-kg sailboat shown in Figure P4.58. the force exerted by the wind on the sailboat is F soil = ( 550 N m/s ) v wind Water exerts a force along the keel (bottom) of the boat that prevents it from moving sideways, as shown in the figure Once the boat starts moving forward, water also exerts a drag force backwards on the boat, opposing the forward motion. If a 17-knot wind (1 knot = 0.514 m/s) is blowing to the east, what is the initial acceleration of the sailboat? Figure P 4.58
The force exerted by the wind on a sailboat is approximately perpendicular 10 the sail and proportional to the component of the wind velocity perpendicular to the sail. For the 800-kg sailboat shown in Figure P4.58. the force exerted by the wind on the sailboat is F soil = ( 550 N m/s ) v wind Water exerts a force along the keel (bottom) of the boat that prevents it from moving sideways, as shown in the figure Once the boat starts moving forward, water also exerts a drag force backwards on the boat, opposing the forward motion. If a 17-knot wind (1 knot = 0.514 m/s) is blowing to the east, what is the initial acceleration of the sailboat? Figure P 4.58
Solution Summary: The author calculates the force exerted by the wind component on the sailboat.
The force exerted by the wind on a sailboat is approximately perpendicular 10 the sail and proportional to the component of the wind velocity perpendicular to the sail. For the 800-kg sailboat shown in Figure P4.58. the force exerted by the wind on the sailboat is
F
soil
=
(
550
N
m/s
)
v
wind
Water exerts a force along the keel (bottom) of the boat that prevents it from moving sideways, as shown in the figure Once the boat starts moving forward, water also exerts a drag force backwards on the boat, opposing the forward motion. If a 17-knot wind (1 knot = 0.514 m/s) is blowing to the east, what is the initial acceleration of the sailboat?
A 137 kg boat is trying to go, from the
origin (as shown in the figure), straight
across the river at a speed 0.7198 m/s in
the y-direction. The current in the river,
however, flows to the right and apply a net
force of 100 N (x-direction).
a) What is the position vector of the boat
after 2 seconds.
b) What is the velocity of the boat after 3
seconds.
Vboat,y
Initial position of the boat is:
Ij =
+
consider a force vector = 300 g at the 40º angle. resolve this vector into its x- and y-components by the following methods: a) graphical: make the x- and y-axes. use a scale of 30 g = 1.0 cm, and draw an arrow of appropriate length at 40º. drop perpendiculars from the tip of the vector to the x- and y-axes. measure the lengths of these lines and hence find the magnitudes of fx and fy. (do not calculate using trigonometry) record the results. b) analytical: compute the magnitudes of fx and fy by using the component method (equations 3-3 and 3-4). record the results.
At a pool, a 3.26 kg life ring is thrown by a lifeguard to a struggling swimmer. The
lifeguard stand is 1.75 m above the water. If air resistance is negligible and the life ring is launch
with a speed of 8.23 m/s at the angle indicated in the figure:
a) Find the height of the life ring and the net force on the life ring at point P.
b) Find how far the life ring lands from the base of the stand.
c) With what velocity did the life ring strike the water at point Q?
30°
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