Layers of 23-cm-thick meat slabs ( k = 0.47 W/m .K , α = 0 .13 × 10 -6 m 2 /s) and initially at a uniform temperature of 7°C are to be frozen by refrigerated air at -30°C flowing at a velocity of 1.4 m/s. The average heat transfer coefficient between the meat and the air is 20 W/m 2 K. Assuming the size of the meat slabs to be large relative to their thickness, determine how long it will take for the center temperature of the slabs to drop to -18°C. Also, determine the surface temperature of the meat slab at that time.
Layers of 23-cm-thick meat slabs ( k = 0.47 W/m .K , α = 0 .13 × 10 -6 m 2 /s) and initially at a uniform temperature of 7°C are to be frozen by refrigerated air at -30°C flowing at a velocity of 1.4 m/s. The average heat transfer coefficient between the meat and the air is 20 W/m 2 K. Assuming the size of the meat slabs to be large relative to their thickness, determine how long it will take for the center temperature of the slabs to drop to -18°C. Also, determine the surface temperature of the meat slab at that time.
Solution Summary: The author explains the time taken by the centre temperature of the slabs to drop to 18 o C and to find the surface temperature.
Layers of 23-cm-thick meat slabs
(
k
=
0.47
W/m
.K
,
α
= 0
.13
×
10
-6
m
2
/s)
and initially at a uniform temperature of 7°C are to be frozen by refrigerated air at -30°C flowing at a velocity of 1.4 m/s. The average heat transfer coefficient between the meat and the air is 20 W/m2 K. Assuming the size of the meat slabs to be large relative to their thickness, determine how long it will take for the center temperature of the slabs to drop to -18°C. Also, determine the surface temperature of the meat slab at that time.
Note:
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