15 kg of steel ball bearings at 100 ° C is immersed in 25 kg of water at 20 ° C . Assuming no loss of heat to or from the container, calculate the final temperature of the water after equilibrium has been attained.Specific heat of steel: 0.4857 kJ / kg / ° KSpecific heat of water: 4.187 kJ / kg / ° K

15 kg of steel ball bearings at 100 ° C is immersed in 25 kg of water at 20 ° C . Assuming no loss of heat to or from the container, calculate the final temperature of the water after equilibrium has been attained.Specific heat of steel: 0.4857 kJ / kg / ° KSpecific heat of water: 4.187 kJ / kg / ° K

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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15 kg of steel ball bearings @ 100 C are immersed in 25 kg of water @ 20 C. Assuming no loss of heat to or from the container, calculate the final temperature of the water after equilibrium has been attained. Specific heat of steel : 0.4857ki(kgK)Specific heat of water : 4.187 kJ(kgK)
8. A 1.90-kg piece of aluminum that has a temperature of -159 °C is added to 1.80 kg of water that has a temperature of 3.5 °C. At equilibrium the temperature is 0.0°C. Assuming that the heat exchanged with the container and the surroundings is negligible, determine the mass of water that has been frozen into ice. grams
There is an 500g container made out of aluminum holding 300g of water. The Water and Aluminum have reached thermal equilibrium at 40 degrees Celsius. A 200g block of iron at a temperature of 0 degrees Celsius is later dropped into the water. Using the specific heat for water=4180J/kg/C. The specific heat for aluminum is 900 J/kg/C. The specific heat for iron is 450 J/kg/C. The final temperature of the three materials will be degrees celsius. The thermal energy of the water changes by Joules. (give an amount and include a + if it increases and a - if it decreases) The thermal energy of the aluminum changes by Joules. (give an amount and include a + if it increases and a - if it decreases) The thermal energy of the iron changes by Joules. (give an amount and unit and include a + if it increases and a - if the value decreases)
Solve the following problem and show your complete solutions. explain your answer for better understanding
4. An iron block of unknown mass at 85oC is dropped into an insulated tank that contains 100L of water at 20oC. At the same time, a paddle wheel driven by a 200W motor is activated to stir the water. It is observed that thermal equilibrium is established after 20min with a final temperature of 24oC. Assuming that the container is perfectly insulated, determine the mass of the iron block (kg). Use C of IRON= 0.44 kJ/kg-K. draw a figure also, and explain each step by step solution.
4. An iron block of unknown mass at 85oC is dropped into an insulated tank that contains 100L of water at 20oC. At the same time, a paddle wheel driven by a 200W motor is activated to stir the water. It is observed that thermal equilibrium is established after 20min with a final temperature of 24oC. Assuming that the container is perfectly insulated, determine the mass of the iron block (kg). Use C of IRON= 0.44 kJ/kg-K. draw a figure also, and explain each step by step solution.
**101. An insulated container is partly filled with oil. The lid of the con- tainer is removed, 0.125 kg of water heated to 90.0 °C is poured in, and the lid is replaced. As the water and the oil reach equilibrium, the volume of the oil increases by 1.20 × 10-³ m³. The density of the oil is 924 kg/m², its specific heat capacity is 1970 J/(kg · C°), and its coefficient of volume expansion is 721 × 10-6 (C°)-!. What is the temperature when the oil and the water reach equilibrium?
A 2.71 g lead weight, initially at 10.3 ∘C, is submerged in 7.54 g of water at 52.2 ∘C in an insulated container. What is the final temperature of both the weight and the water at thermal equilibrium? Express the temperature in Celsius to three significant figures.
A beaker of water sits in the sun until it reaches an equilibrium temperature of30°C. The beaker is made of 100 g of aluminum and contains 180 g of water. In an attempt to cool this system, a small block of ice at 0°C is added to the water. a. Determine the exact mass of ice needed to melt (giving up its latent heat of fusion) and bring the water and beaker temperature down to 0°C. b. If the ice block has a mass of 100 g, determine the final temperature of the system. If it turns out that Tf = 0°C, determine how much ice remains unmelted.
A beaker of water sits in the sun until it reaches an equilibrium temperature of30°C.The beaker is made of 100 g of aluminum and contains 180 g of water. In an attempt to cool this system, a small block of ice at 0°C is added to the water. a. Determine the exact mass of ice needed to melt (giving up its latent heat of fusion) and bring the water and beaker temperature down to 0°C. b. If the ice block has a mass of 100 g, determine the final temperature of the system. If it turns out that Tf = 0°C, determine how much ice remains unmelted. c. Repeat your calculations for 50 g of ice.
A 30.0-g ice cube floats in 212 g of water in a 100-g copper cup; all are at a temperature of 0°C. A piece of lead at 99.0°C is dropped into the cup, and the final equilibrium temperature is 12.0°C. What is the mass of the lead? (The heat fusion and specific heat of water are 3.33 x 105 J/kg and 4,186 J/kg - °C, respectively. The specific heat of lead and copper are 128 J/kg · °C and 387 J/kg - °C, respectively.)
There's a copper calorimeter container with the mass 0.2 kg and has 0.32 kg of H2O and also 0.036 kg of ice (thermal equilibrium at atm). If we drop 1.5 kg of lead at a temperature of 200 Celsius into calorimeter container, find the final temperature (in Celsius). Please show work Lead=131J/kgK Copper=390J/kg.K H2O = Cw = 4190 J/kg.K & LF = 3.34 x 105 J/kg