Two metal rods are being heated in an oven with uniform ambient temperature of 1000°C and convection heat transfer coefficient of 25 W/m 2 K. Rod A is made of aluinimini ( p = 2702 Kg/m 3 , c p = 903 J/kg .K , k = 237 W/m .K) and and rod B is made of stainless steel ( p = 8238 Kg/m 3 , c p = 468 J/kg .K , k = 13 .4 W/m .K) . Both rods have a diameter of 25 mm and a length of 1 m. If the initial temperature of both rods is 15°C, determine the average temperatures of both rods aller 5 min.
Two metal rods are being heated in an oven with uniform ambient temperature of 1000°C and convection heat transfer coefficient of 25 W/m 2 K. Rod A is made of aluinimini ( p = 2702 Kg/m 3 , c p = 903 J/kg .K , k = 237 W/m .K) and and rod B is made of stainless steel ( p = 8238 Kg/m 3 , c p = 468 J/kg .K , k = 13 .4 W/m .K) . Both rods have a diameter of 25 mm and a length of 1 m. If the initial temperature of both rods is 15°C, determine the average temperatures of both rods aller 5 min.
Two metal rods are being heated in an oven with uniform ambient temperature of 1000°C and convection heat transfer coefficient of 25 W/m2 K. Rod A is made of aluinimini
(
p
=
2702
Kg/m
3
,
c
p
= 903 J/kg
.K , k = 237 W/m
.K)
and and rod B is made of stainless steel
(
p
=
8238
Kg/m
3
,
c
p
= 468 J/kg
.K , k = 13
.4 W/m
.K)
. Both rods have a diameter of 25 mm and a length of 1 m. If the initial temperature of both rods is 15°C, determine the average temperatures of both rods aller 5 min.
A carbon steel ball with 27.00-mm diameter is pressed together with an aluminum ball
with a 36.00-mm diameter by a force of 11.00 N. Determine the maximum shear
stress and the depth at which it will occur for the aluminum ball. Assume the figure
given below, which is based on a typical Poisson's ratio of 0.3, is applicable to estimate
the depth at which the maximum shear stress occurs for these materials.
1.0
0.8
Ratio of stress to Pma
9 0.6
στ
24
0.4
Tmax
0.2
0
0.5a
a
1.5a
Z
2a
2.5a
За
Distance from contact surface
The maximum shear stress is determined to be
MPa.
The depth in the aluminum ball at which the maximum shear stress will occur is
determined to be [
mm.
Show all work please
Draw top, side, front view With pen(cil) and paper
Multi view drawing and handwriting all of it
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