Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 4, Problem 52P
Interpretation Introduction
Interpretation:
The experiments that needs to be designed to determine the factors affecting the DNA double helix structural stability needs to be explained.
Concept introduction:
The stability of a DNA double helical structure depends on the hydrogen bonding between bases and base-stacking interaction between adjacent bases.
The bases present in a single strand of DNA have polar amido, amidino, guanidino and carbonyl groups which form hydrogen bonds with water, but when the double helical structure is formed some of the bond breaks as the bases combine to form inter-base hydrogen bonds. The change in enthalpy, in this case, is due to the difference of energy in the new hydrogen bond formed and old hydrogen bond is broken.
The stability of base stacks of the double helix depends on the DNA sequence. Some sequences are more stable than others, hence the nearest base stack is important to state the stability of the double helical structure.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Draw and name each alcohol and classify it as primary, secondary, or tertiary. Explain your answer thoroughly.
Draw the product of each reaction. If there are multiple products, draw only the major product. Explain your answer thoroughly.
Identify the type of bond in the following disaccharides. Number your carbons to show work. Explain your answer thoroughly. Draw the number of carbons also.
Chapter 4 Solutions
Biochemistry
Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
- Draw and explain your answer thoroughly: a. What is the molar mass of aspirin (C9H8O4)?b. What is the mass of 0.00225mol of aspirin?c. How many moles of aspirin are present in 500mg of aspirin?arrow_forwardGeranylgeranyl pyrophosphate 5 is converted by general acid-base catalysis to 6, and then to the natural product 7. For clarity only limited atom numbers are shown, but the main chain carbons are numbered 1 to 16, and the off-chain methyl substituents are numbered 17-20. A. Based on what you specified in A, use curly arrows on the drawing above to convert 5 to 6, and 6 to 7. Invoke general acids and general bases as needed, and draw in hydrogens as necessary . B. On the structure of 7, write in the atom numbers for the carbons marked with an asteriskarrow_forwardα-Pinene (4) is synthesized enzymatically from nerol pyrophosphate 1. Drawn an arrow-pushing mechanism from 1 to 2 to 3 to 4; add explicit hydrogens to clarify, if needed.arrow_forward
- A reverse phase column chromatography separates proteins according to their polarity. Which pentapeptide will be eluted FIRST when chromatographed at pH 7 using a reverse phase column such as a C-18 column? Peptide Sequence (from N-terminal to C-terminal) AKGED GAAVF ALLLI MCYAG GAAVF MCYAG ALLLI AKGEDarrow_forwardMelting of three DNA samples with varying lengths was monitored by increase of ultraviolet light absorbance at 260 nm. Which is the shortest DNA? A B Carrow_forwardSelect the CORRECT description of the peptide bond. The peptide bond can freely rotate around the peptide bond. The peptide bond is non-polar, hydrophobic and does not have a dipole. The peptide bond is most stable in the cis configuration. The peptide bond is rigid and planar. The peptide bond has a mix of single and double bond characters. The peptide bond is most stable in the trans configuration.arrow_forward
- Below is a fractional saturation curve for O2 binding to adult hemoglobin. Assume that curve Y represents a system at pH 7.4 and with a normal physiological level of 2,3-BPG. Curve Z represents a system that ___________________ Curve Z: is at pH 7.4 with a higher than normal physiological level of 2,3-BPG. is at pH 7.4 with a normal physiological level of 2,3-BPG but with a decreased level of CO2. has a higher pH with a normal physiological level of 2,3-BPG. has a higher pH with a lower than physiological level of 2,3-BPG.arrow_forwardWhich is a homotropic positive effector of aspartate transcarbamoylase (ATCase)? oxygen CTP aspartate ATParrow_forwardThe reaction scheme shows the mechanism of chymotrypsin-catalyzed peptide hydrolysis. Select ALL CORRECT statements regarding the chymotrypsin mechanism. Serine is the nucleophile in the step 3. Histidine is a general base in the step 2. Carbonyl carbon is the electrophile in the step 3. Histidine is a general acid in the step 4. Carbonyl carbon is the nucleophile in the step 3. This is an example of covalent catalysis. Aspartate is the electrophile in the step 3. Histidine is the nucleophile in the step 3.arrow_forward
- The following shows a protein with mostly beta sheet secondary structures. Which force stabilizes the beta sheet secondary structure of proteins? hydrophobic interactions between nonpolar amino acid side chains within the protein. electrostatic interactions between lysine and aspartic acid residues within the protein. hydrogen bonding between hydrogen bond donors and hydrogen bond acceptors of the peptide backbone. covalent disulfide linkages between cysteine residues within the protein.arrow_forwardThe Lineweaver-Burk plot was obtained when enzyme inhibition study was done in the absence and presence of 0.50 mM inhibitor. Answer the following questions using correct units and significant figures: (a) What is the mode of inhibition, competitive, uncompetitive, mixed, or noncompetitive? Explain your answer. (b) What can you say about the finding site for the inhibitor in relation to the active site of the enzyme? Explain your answer. (c) Calculate the Km and Vmax in the absence of inhibitor. (d) Calculate the Km and Vmax in the presence of 0.50 mM inhibitor. (e) Calculate the KI of the inhibitor using the given equations for reversible inhibition. Which has a higher affinity, the substrate or the inhibitor? How can you tell?arrow_forwardWhich peptide sequence is most likely to be found in the interior portion of a water-soluble globular protein? GGDGEMG DSKSTEG GAIVLWL IVAKSLIarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
Biology: The Dynamic Science (MindTap Course List)
Biology
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Cengage Learning
Molecular Techniques: Basic Concepts; Author: Dr. A's Clinical Lab Videos;https://www.youtube.com/watch?v=7HFHZy8h6z0;License: Standard Youtube License