NEW PERSP.ON COMP.CONCEPTS-PACKAGE
17th Edition
ISBN: 9781337761116
Author: Carey
Publisher: CENGAGE L
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Question
Chapter 4, Problem 4CP1
Program Plan Intro
(a)
Program Plan:
To set sd_back2.png as background of body.
Program Plan Intro
(b)
To set radial-gradient circle placed at given coordinates containing white color stopping at 15% of gradient with given color value rgbastopping at 50%.
Program Plan Intro
(c)
To set radial-gradient circle placed at given coordinates containing white color stopping at 15% of gradient with given color value rgba stopping at 30%.
Program Plan Intro
(d)
To set radial-gradient circle placed at given coordinates containing white color stopping at 20% of gradient with given color value rgba stopping at 45%.
Program Plan Intro
(e)
To set radial-gradient as background of body with size 5% in vertical and horizontal directions with white color stopping at 15% followed by given color stopping at 40 %.
Program Plan Intro
(f)
To set radial-gradient as background of body with color rgb(151,151,151).
Expert Solution & Answer
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Students have asked these similar questions
The next problem concerns the following C code:
/copy input string x to buf */
void foo (char *x) {
char buf [8];
strcpy((char *) buf, x);
}
void callfoo() {
}
foo("ZYXWVUTSRQPONMLKJIHGFEDCBA");
Here is the corresponding machine code on a Linux/x86 machine:
0000000000400530 :
400530:
48 83 ec 18
sub
$0x18,%rsp
400534:
48 89 fe
mov
%rdi, %rsi
400537:
48 89 e7
mov
%rsp,%rdi
40053a:
e8 di fe ff ff
callq
400410
40053f:
48 83 c4 18
add
$0x18,%rsp
400543:
c3
retq
400544:
0000000000400544 :
48 83 ec 08
sub
$0x8,%rsp
400548:
bf 00 06 40 00
mov
$0x400600,%edi
40054d:
e8 de ff ff ff
callq 400530
400552:
48 83 c4 08
add
$0x8,%rsp
400556:
c3
This problem tests your understanding of the program stack. Here are some notes to
help you work the problem:
⚫ strcpy(char *dst, char *src) copies the string at address src (including
the terminating '\0' character) to address dst. It does not check the size of
the destination buffer.
• You will need to know the hex values of the following characters:
1234
3. Which line prevents compiler optimization? Circle one: 1234
Suggested solution:
Store strlen(str) in a variable before the if statement.
⚫ Remove the if statement.
Replace index 0 && index < strlen(str)) {
5 }
}
=
str [index] = val;
Character Hex value | Character Hex value Character Hex value
'A'
0x41
'J'
Ox4a
'S'
0x53
'B'
0x42
'K'
0x4b
"T"
0x54
0x43
'L'
Ox4c
'U'
0x55
0x44
'M'
0x4d
'V'
0x56
0x45
'N'
Ox4e
'W'
0x57
0x46
'0'
Ox4f
'X'
0x58
0x47
'P'
0x50
'Y'
0x59
0x48
'Q'
0x51
'Z'
Ox5a
'T'
0x49
'R'
0x52
'\0'
0x00
Now consider what happens on a Linux/x86 machine when callfoo calls foo with
the input string "ZYXWVUTSRQPONMLKJIHGFEDCBA".
A. On the left draw the state of the stack just before the execution of the instruction
at address Ox40053a; make sure to show the frames for callfoo and foo and
the exact return address, in Hex at the bottom of the callfoo frame.
Then, on the right, draw the state of the stack just after the instruction got
executed; make sure to show where the string "ZYXWVUTSRQPONMLKJIHGFEDCBA"
is placed and what part, if any, of the above return address has been overwritten.
B. Immediately after the ret instruction at address 0x400543 executes, what is
the value of the program counter register %rip?…
Chapter 4 Solutions
NEW PERSP.ON COMP.CONCEPTS-PACKAGE
Ch. 4.1 - Prob. 1QCCh. 4.1 - Prob. 2QCCh. 4.1 - Prob. 3QCCh. 4.1 - Prob. 4QCCh. 4.1 - Prob. 5QCCh. 4.1 - Prob. 6QCCh. 4.1 - Prob. 7QCCh. 4.1 - Prob. 8QCCh. 4.1 - Prob. 9QCCh. 4.2 - Prob. 1QC
Ch. 4.2 - Prob. 2QCCh. 4.2 - Prob. 3QCCh. 4.2 - Prob. 4QCCh. 4.2 - Prob. 5QCCh. 4.2 - Prob. 6QCCh. 4.2 - Prob. 7QCCh. 4.2 - Prob. 8QCCh. 4.2 - Prob. 9QCCh. 4.3 - Prob. 1QCCh. 4.3 - Prob. 2QCCh. 4.3 - Prob. 3QCCh. 4.3 - Prob. 4QCCh. 4.3 - Prob. 5QCCh. 4.3 - Prob. 6QCCh. 4.3 - Prob. 7QCCh. 4.3 - Prob. 8QCCh. 4.3 - Prob. 9QCCh. 4 - Prob. 1RACh. 4 - Prob. 2RACh. 4 - Prob. 3RACh. 4 - Prob. 4RACh. 4 - Prob. 5RACh. 4 - Prob. 6RACh. 4 - Prob. 7RACh. 4 - Prob. 8RACh. 4 - Prob. 9RACh. 4 - Prob. 10RACh. 4 - Prob. 11RACh. 4 - Prob. 12RACh. 4 - Prob. 13RACh. 4 - Prob. 14RACh. 4 - Prob. 15RACh. 4 - Prob. 16RACh. 4 - Prob. 17RACh. 4 - Prob. 18RACh. 4 - Prob. 19RACh. 4 - Prob. 20RACh. 4 - Prob. 21RACh. 4 - Prob. 22RACh. 4 - Prob. 23RACh. 4 - Prob. 24RACh. 4 - Prob. 25RACh. 4 - Prob. 1CP1Ch. 4 - Prob. 2CP1Ch. 4 - Prob. 3CP1Ch. 4 - Prob. 4CP1Ch. 4 - Prob. 5CP1Ch. 4 - Prob. 6CP1Ch. 4 - Prob. 7CP1Ch. 4 - Prob. 8CP1Ch. 4 - Prob. 9CP1Ch. 4 - Prob. 10CP1Ch. 4 - Prob. 11CP1Ch. 4 - Prob. 1CP2Ch. 4 - Prob. 2CP2Ch. 4 - Prob. 3CP2Ch. 4 - Prob. 4CP2Ch. 4 - Prob. 5CP2Ch. 4 - Prob. 6CP2Ch. 4 - Prob. 7CP2Ch. 4 - Prob. 8CP2Ch. 4 - Prob. 9CP2Ch. 4 - Prob. 10CP2Ch. 4 - Prob. 11CP2Ch. 4 - Prob. 12CP2Ch. 4 - Prob. 1CP3Ch. 4 - Prob. 2CP3Ch. 4 - Prob. 3CP3Ch. 4 - Prob. 4CP3Ch. 4 - Prob. 5CP3Ch. 4 - Prob. 6CP3Ch. 4 - Prob. 7CP3Ch. 4 - Prob. 8CP3Ch. 4 - Prob. 9CP3Ch. 4 - Prob. 10CP3Ch. 4 - Prob. 11CP3Ch. 4 - Prob. 12CP3Ch. 4 - Prob. 13CP3Ch. 4 - Prob. 1CP4Ch. 4 - Prob. 2CP4Ch. 4 - Prob. 3CP4Ch. 4 - Prob. 4CP4Ch. 4 - Prob. 5CP4Ch. 4 - Prob. 6CP4
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