Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Chapter 4, Problem 49E
To determine

To Explain: the appropriate graphical displays and summary statistics.

Expert Solution & Answer
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Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 49E , additional homework tip  1

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 49E , additional homework tip  2

Calculation:

Median: First sort the data in ascending order. Following is the sorted data:

293.4, 358.7, 367.9, 381.9, 386.8, 408.3, 414.4, 418.4, 423.6, 426.7, 435.7, 435.7, 447.5,

449.8, 451.1, 454.6, 454.8, 458.5, 460.6, 461.7, 470.1, 482, 488.2, 491.7, 496, 505, 507.8,

508.8, 511.8, 512, 526.6, 526.9, 527.7, 529.4, 532.7, 537.1, 541.6, 544.4, 544.4, 545.5,

550.5, 552.5, 553.7, 555.1, 558.5, 564.4, 576.3, 578.6, 614.2, 615

These are 50 values so median is the average of 25th (496) and 26th (505) values. So median will be

  Median=496+5052=500.5gallons

Mean: sum of these 50 values is 24438.6 so mean will be

  Mean=24438.650=488.8gallons

So standard deviation will be

  SD(s)=(xx¯)n1=231147.849=4717.30=68.7gallons

So standard deviation is 68.7 gallons

IQR:

To find IQR let us first find Q1 and Q3 . Lower quartile is middle value of lower half.

Lower half of data has 25 values. Upper half of data is

293.4, 358.7, 367.9, 381.9, 386.8, 408.3, 414.4, 418.4, 423.6, 426.7, 435.7, 435.7, 447.5,

449.8, 451.1, 454.6, 454.8, 458.5, 460.6, 461.7, 470.1, 482, 488.2, 491.7, 496

The lower quartile is 13th value so

  Q1=447.5

Upper half of data has 25 values. upper half of data is

505, 507.8, 508.8, 511.8, 512, 526.6, 526.9, 527.7, 529.4, 532.7, 541.6, 544.4,

544.4, 545.5, 550.5, 552.5, 553.7, 555.1, 558.5, 564.4, 576.3, 578.6, 614.2, 615

The lower quartile is 13th value so

  Q3=544.4

Therefore IQR is

  IQR=Q3Q1=544.4447.5=96.9gallons

Median and mean of the data is 500.5 gallons and 488.8 gallons respectively. Standard deviation of data is a 68.7 gallons means state by consumption per person varies about 68.7 gallons. Distribution is skewed to left slightly. So median works as a good measure of centre of distribution in comparison of mean.

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