Concept explainers
(a)
Interpretation:
The equation which relates the concentration of
Concept introduction:
The equation of a straight line on semi-log plot is,
Given two points
The value of intercept can be calculated using this slope and any one of the given points.
(b)
Interpretation:
The compliance of the process with the given EPA regulation is to be determined.
Concept introduction:
A flowchart is the complete representation of a process through boxes or other shapes which represents process units and arrows that represents the input and output of the process. The flowchart must be fully labelled to infer important data about the process involved.
(c)
Interpretation:
The percentage of
Concept introduction:
Stoichiometry is based on the law of conservation of mass and is used to calculate the amounts of reactants and products in a chemical reaction.
The total mass of the reactants is always equal to the total mass of the products.
The formula to calculate the mass flowrate of a component
Here,
A flowchart is the complete representation of a process through boxes or other shapes which represents process units and arrows that represents the input and output of the process. The flowchart must be fully labelled to infer important data about the process involved.
(d)
Interpretation:
The reason for the discontinuity of the old EPA regulation after the new EPA regulation was imposed is to be determined and explained.
Concept introduction:
Mole fraction of a component in a mixture can be altered by dilution of the mixture. Mole fraction is referred to as the number of moles of that component divided by the total moles of the mixture.
Due to dilution of the mixture, the total moles of the mixture are increased but moles of the component being the same. Thus, mole fraction is decreased.
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Chapter 4 Solutions
ELEMENTARY PRINCIPLES OF CHEM. PROCESS.
- please, provide me with right resultsarrow_forwardEx. HW. A vertical glass tube, 2cm ID & 5m long in heated uniformly over its length. The water enter at (200-204 C) & 68.9 bar calculated the pressure drop if the flowrate 0.15 Kg/s & the power applied as a heat to the fluid is 100KW using the homogeneous model. Given that enthalpy at inlet temp.=0.87MJ/Kg, enthalpy saturation temp (285C)=1.26 MJ/Kg and μl=0.972*10-4 Ns/m2, μG=2.89*10-5 Ns/m2, UG=2.515*10-2m3/Kg and the change in UG over range of pressure=-4.45*10-4m3/Kg/bar.arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forward
- and the viscosity of the water is 1.24 × 104 Nsm 2. Answer: Slug flow 1. Determine the range of mean density of a mixture of air in a 50:50 oil-water liquid phase across a range of gas void fractions. The den- sity of oil is 900 kgm³, water is 1000 kgm³, and gas is 10 kgm³.arrow_forwardA chemical reaction takes place in a container of cross-sectional area 50.0 cm2. As a result of the reaction, a piston is pushed out through 15 cm against an external pressure of 121 kPa. Calculate the work done (in J) by the system.arrow_forwardExample 7.2 Steam is generated in a high pressure boiler containing tubes 2.5 m long and 12.5 mm internal diameter. The wall roughness is 0.005 mm. Water enters the tubes at a pressure of 55.05 bar and a temperature of 270°C, and the water flow rate through each tube is 500 kg/h. Each tube is heated uniformly at a rate of 50 kW. Calle (a) Estimate the pressure drop across each tube (neglecting end effects) using (i) the homogeneous flow model and (ii) the Martinelli-Nelson correlation. (b) How should the calculation be modified if the inlet temperature were 230°C at the same pressure?arrow_forward
- Please solve this question by simulation in aspen hysysarrow_forward(11.35. For a binary gas mixture described by Eqs. (3.37) and (11.58), prove that: 4812 Pу132 ✓ GE = 812 Py1 y2. ✓ SE dT HE-12 T L = = (812 - 7 1/8/123) d² 812 Pylyz C=-T Pylyz dT dT² See also Eq. (11.84), and note that 812 = 2B12 B11 - B22. perimental values of HE for binary liquid mixtures ofarrow_forwardplease provide me the solution with more details. because the previous solution is not cleararrow_forward
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