Concept explainers
(a)
Interpretation: The most stable arrangement of substituents on the six-membered ring by using chair form is to be drawn.
Concept introduction: Glucose is a monosaccharide. It is made by the plants during the process of photosynthesis. The molecular formula of glucose is
(b)
Interpretation: The chair form of glucose is to be converted into wedge-dash representation.
Concept introduction: Glucose is a monosaccharide. It is a simple sugar that is made by the plants during the process of photosynthesis. The molecular formula of glucose is
(c)
Interpretation: A constitutional isomer of glucose is to be drawn.
Concept introduction: Constitutional isomers have same molecular formula but the connectivity of the atoms is different.
(d)
Interpretation: The stereoisomer of glucose that has an axial OH group on one carbon is to be drawn.
Concept introduction: The two stereoisomers of glucose are
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ORGANIC CHEMISTRY
- Shown below is Streptomycin, and Neomycin B. Circle and label as many functional groups in these molecules as you can. a. Label each chiral carbon in Streptomycin. How many total stereoisomers exist for Streptomycin? b. Label each chiral carbon in Neomycin B. How many total stereoisomers exist for Neomycin B?arrow_forwardOH a. Draw the cis and trans isomer of the molecule above. b. Draw the chair form of the trans isomer of the molecule. C. Draw the flipped chair form of the trans isomer of the molecule. d. What is the more stable chair form?arrow_forwardConstruct a model in which a tetrahedral carbon atom has four different colored model atoms attached to it- red, green, orange and white representing 4 different atoms attached to the central atom. a) Does the atom have a plane of symmetry? why or why not? b) Now replace the green atom in your model with a second orange atom. Now two of the groups attached to the carbon atom are identical. Does the model now have a plane of symmetry? Describe it. c)A carbon atom has four different groups attached to the stereogenic center. Draw structural formulas for the following compound and mark stereogenic centers with as asterisk: 1-bromobutane, 2-bromobutane, 1,2-dibromobutane, 1,4-dibromobutane, 2,3-dibromobutane.arrow_forward
- .Draw the strongest IMF that can form between each structure below and a water molecule. Draw a stereoisomer of each molecule below. a. HOarrow_forwardLabel the anomeric carbonarrow_forward20. Circle any two structures. Below each structure, write the name of the compound. Onl graded if you draw more than two. Use cis or trans in the name.arrow_forward
- • Question 5: Label each stereogenic center as R or S. CH₂ a. CH₂CH₂ b. CH H 1 NH₂ H CH3 CH₂CH₂ T C. D CI CH3 d. Br C ICH₂ H e. f. H* HO C HOOC CH₂ HO CH(CH3)2 -C₂ C CH3 SH NH₂ H CH3 g. h. .CI CIarrow_forward10. Draw the enantiomer of the following molecule. Circle each chiral carbon in the original molecule. a. HO Но H- H- FHO- H- HO- HO,arrow_forwardConvert each compound to a skeletal structure. a. CH3(CH2)7CH3 window open b. 1,1−diethylcyclohexane draw structure ... c. (CH3CH2)2CHCH2CH2CH3 draw structure ...arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning