A very small circular cylinder of radius R t is rotating angular velocity ω i , inside a much larger concentric cylinder of radius R 0 that is rotating at angular velocity ω 0 . A liquid of density ρ and viscosity μ is confined between the two cylinders, as in Fig. P4-41. Gravitational and end effects can be neglected (the flow is two-dimensional into the page). If ω j = ω 0 and a long time has passed. generate an expression for the tangential velocity profile. u θ as a function of (at most) r , ω , R j , R o , ρ . and μ . where ω = ω 1 = ω 0 . Also, calculate the torque exerted by the fluid on the inner cylinder and on the outer cylinder.
A very small circular cylinder of radius R t is rotating angular velocity ω i , inside a much larger concentric cylinder of radius R 0 that is rotating at angular velocity ω 0 . A liquid of density ρ and viscosity μ is confined between the two cylinders, as in Fig. P4-41. Gravitational and end effects can be neglected (the flow is two-dimensional into the page). If ω j = ω 0 and a long time has passed. generate an expression for the tangential velocity profile. u θ as a function of (at most) r , ω , R j , R o , ρ . and μ . where ω = ω 1 = ω 0 . Also, calculate the torque exerted by the fluid on the inner cylinder and on the outer cylinder.
Solution Summary: The author explains the expression for tangential velocity profile, which is given as underset_u=rw.
A very small circular cylinder of radius Rtis rotating angular velocity
ω
i
, inside a much larger concentric cylinder of radius R0that is rotating at angular velocity
ω
0
. A liquid of density
ρ
and viscosity
μ
is confined between the two cylinders, as in Fig. P4-41. Gravitational and end effects can be neglected (the flow is two-dimensional into the page). If
ω
j
=
ω
0
and a long time has passed. generate an expression for the tangential velocity profile.
u
θ
as a function of (at most)
r
,
ω
,
R
j
,
R
o
,
ρ
. and
μ
. where
ω
=
ω
1
=
ω
0
. Also, calculate the torque exerted by the fluid on the inner cylinder and on the outer cylinder.
Given answers to be: i) 14.65 kN; 6.16 kN; 8.46 kN ii) 8.63 kN; 9.88 kN iii) Bearing 6315 for B1 & B2, or Bearing 6215 for B1
(b)
A steel 'hot rolled structural hollow section' column of length 5.75 m, has
the cross-section shown in Figure Q.5(b) and supports a load of 750 kN.
During service, it is subjected to axial compression loading where one end
of the column is effectively restrained in position and direction (fixed) and
the other is effectively held in position but not in direction (pinned).
i)
Given that the steel has a design strength of 275 MN/m², determine
the load factor for the structural member based upon the BS5950
design approach using Datasheet Q.5(b).
[11]
ii)
Determine the axial load that can be supported by the column
using the Rankine-Gordon formula, given that the yield strength of
the material is 280 MN/m² and the constant *a* is 1/30000.
[6]
300
600
2-300 mm
wide x 5 mm
thick plates.
Figure Q.5(b)
L=5.75m
Pinned
Fixed
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